Algebra Pre-Algebra and Basic Algebra Math Forum

 August 26th, 2019, 06:42 PM #1 Newbie   Joined: May 2018 From: United States Posts: 8 Thanks: 0 Math Focus: Algebra Algebra Pythagorean Theorem Hello all. I was wondering how to solve this particular problem. I am not certain I am setting it up correctly, and I think it's likely I don't have it quite right. Any help is deeply appreciated. (from textbook) "Use the Pythagorean Theorem to find the missing side length. Leave answer in simplest form." $\displaystyle a= \frac{2}{3}b , c=12$ (my attempt) $\displaystyle \left (\frac{2}{3}b \right )^2+b^2=12^2$ Next I raise the contents of my first parenthesis to the second power, then combine like terms $\displaystyle b^2$. Thus $\displaystyle \frac{4}{9}b +b^2$ $\displaystyle \frac{13}{9}b^2 =144$ \Multiply both sides by reciprocal of b's coefficient $\displaystyle b^2=\frac{1296}{13}$ My guess at the solution is the same as above, just apply radical to right and remove b's 2nd power. I appreciate any and all input. My book provides no solution, so I don't know whether this is correct or miles off the mark. Last edited by skipjack; August 26th, 2019 at 10:59 PM. August 26th, 2019, 06:46 PM #2 Senior Member   Joined: Sep 2015 From: USA Posts: 2,636 Thanks: 1472 This is correct though as they are lengths, and thus non-negative, you could go further and say that $b = \dfrac{36}{\sqrt{13}}=\dfrac{36\sqrt{13}}{13}$ Thanks from Ebba Sen Pai Tags algebra, pythagorean, theorem Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post sidra76 Geometry 10 March 9th, 2016 08:23 PM Perlita Geometry 1 May 19th, 2014 09:46 AM Skyer New Users 11 August 1st, 2011 06:15 AM johnny Geometry 10 September 20th, 2010 05:32 PM mohanned karkosh Geometry 1 October 22nd, 2007 06:13 AM

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