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 June 20th, 2019, 12:28 PM #1 Senior Member   Joined: Jan 2012 Posts: 140 Thanks: 2 Question related with Binomial Theorem How can we find the index 'n' of the binomial $\displaystyle \left ( \frac{x}{5}+\frac{2}{5} \right )^{n}$, $\displaystyle n\epsilon N$ if the 9th term of the expansion has numerically the greatest coefficient. Thx. June 20th, 2019, 01:59 PM #2 Global Moderator   Joined: May 2007 Posts: 6,852 Thanks: 743 The coefficients are $\binom{n}{k}$ for $0\le k\le n$. The maximum is in the middle. If $n$ is even then the max is at $\frac{n}{2}$. If $n$ is odd, it is max at a pair at $\frac{n-1}{2}$ and $\frac{n+1}{2}$. You can work it out yourself. Be careful, $k$ starts at $0$. Thanks from topsquark June 20th, 2019, 02:07 PM   #3
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Quote:
 Originally Posted by mathman The coefficients are $\binom{n}{k}$ for $0\le k\le n$. The maximum is in the middle. If $n$ is even then the max is at $\frac{n}{2}$. If $n$ is odd, it is max at a pair at $\frac{n-1}{2}$ and $\frac{n+1}{2}$. You can work it out yourself. Be careful, $k$ starts at $0$.
But as given 9th term is the greatest (numerically), there should be (?) only one middle term. So 'n' should (or must?) be even? Further, what value(s) 'x' can take because it is also unknown in the question. Thx.

Last edited by happy21; June 20th, 2019 at 02:09 PM. June 20th, 2019, 04:39 PM   #4
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Quote:
 Originally Posted by mathman The coefficients are $\binom{n}{k}$ for $0\le k\le n$. The maximum is in the middle. If $n$ is even then the max is at $\frac{n}{2}$. If $n$ is odd, it is max at a pair at $\frac{n-1}{2}$ and $\frac{n+1}{2}$. You can work it out yourself. Be careful, $k$ starts at $0$.
This is not correct. The coefficient of $x^k$ is actually $2^{n-k} 5^{-n} \binom{n}{k}$. June 21st, 2019, 12:34 AM   #5
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 Originally Posted by SDK This is not correct. The coefficient of $x^k$ is actually $2^{n-k} 5^{-n} \binom{n}{k}$.
And after that? June 21st, 2019, 01:29 PM   #6
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Quote:
 Originally Posted by happy21 And after that?
Assuming he wants the coefficient of a polynomial in x, you are correct. I was assuming something different. Tags binomial, question, related, theorem Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Swyfte Calculus 4 December 12th, 2017 01:57 PM Richard Fenton Number Theory 3 January 13th, 2015 09:29 AM natt010 Real Analysis 12 December 30th, 2013 04:13 PM SH-Rock Probability and Statistics 1 January 6th, 2011 04:08 PM SH-Rock Calculus 1 December 31st, 1969 04:00 PM

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