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 Algebra Pre-Algebra and Basic Algebra Math Forum

 June 4th, 2019, 03:28 PM #1 Senior Member   Joined: Mar 2019 From: TTF area Posts: 126 Thanks: 1 Algebra what is the actual answer ? $$(a-b)^2=a^2-b^2$$ Which values of a and b show that this is not true? June 4th, 2019, 03:59 PM #2 Member   Joined: Oct 2018 From: USA Posts: 89 Thanks: 61 Math Focus: Algebraic Geometry $(a-b)^{2} = a^{2} -2ab + b^{2} = a^{2}-b^{2}$ Subtract $a^{2}$ both sides $-2ab = -2b^{2}$ $a=b$ So just choose any $a$ and $b$ such that $a \neq b$ (edit) and $b \neq 0$ as Romsek mentioned Thanks from topsquark and helpmeddddd Last edited by Greens; June 4th, 2019 at 04:25 PM. June 4th, 2019, 04:15 PM #3 Senior Member   Joined: Sep 2015 From: USA Posts: 2,549 Thanks: 1399 $(a-b)^2 = a^2 - 2ab + b^2$ $a^2 - 2ab + b^2 = a^2 - b^2$ $2b^2 = 2ab$ $\text{If$b = 0$this is true$\forall a$}$ $\text{otherwise$b=a$}$ $\text{So the original equation is only true if$b=0 \vee a=b$}$ Thanks from topsquark and helpmeddddd June 4th, 2019, 10:06 PM #4 Senior Member   Joined: Mar 2019 From: TTF area Posts: 126 Thanks: 1 What if: $$(a â€“ b)^2= a^2â€“ b^2$$ Which values of a and b show that this is not true? A. a = 1, b = 0 $\hspace{1cm}$ B. a = 1, b = 1 C. a = â€“1, b = â€“1 $\hspace{0.58cm}$ D. a = â€“1, b = 0 E. a = 1, b = â€“1 Thanks for those replies. How about this? Last edited by skipjack; June 5th, 2019 at 08:04 AM. June 5th, 2019, 03:53 AM #5 Senior Member   Joined: Mar 2019 From: iran Posts: 318 Thanks: 14 E June 5th, 2019, 05:28 AM #6 Senior Member   Joined: Oct 2009 Posts: 863 Thanks: 328 You seriously can't plug in the values and see whether it equals?? Thanks from topsquark and Otis Tags actual, algebra, answer Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post mdocka1 Computer Science 1 March 30th, 2017 12:04 AM omoplata Algebra 2 March 7th, 2012 02:15 PM jjjsingha Algebra 1 June 25th, 2008 08:43 PM

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