May 20th, 2019, 08:00 PM  #1 
Senior Member Joined: Mar 2019 From: TTF area Posts: 180 Thanks: 1  Algebra word problem
The formula for the length of the hypotenuse of a rightangled triangle, whose short sides are p, q is r² = p² + q² 1. Make p the subject of this formula. 2. Evaluate the shortest side of a rightangled triangle, if the other two sides have lengths given by q = 9.3 and r = 11.4. State the answer accurate to 1 d.p. Last edited by skipjack; May 21st, 2019 at 08:26 AM. 
May 20th, 2019, 08:47 PM  #2 
Senior Member Joined: Oct 2018 From: USA Posts: 102 Thanks: 77 Math Focus: Algebraic Geometry 
$\displaystyle r^{2} = p^{2}+q^{2}$ $\displaystyle r^{2}  q^{2} = p^{2}$ $\displaystyle \sqrt{r^{2}  q^{2}} = p$ You should be able to go from here, if not, let me know. Last edited by Greens; May 20th, 2019 at 08:47 PM. Reason: Latex 
May 20th, 2019, 09:38 PM  #3 
Senior Member Joined: Mar 2019 From: TTF area Posts: 180 Thanks: 1 
So does p = √(r+q)(rq), √(r+q)(rq)?
Last edited by skipjack; May 21st, 2019 at 08:32 AM. 
May 20th, 2019, 11:39 PM  #4 
Senior Member Joined: Oct 2018 From: USA Posts: 102 Thanks: 77 Math Focus: Algebraic Geometry  
May 21st, 2019, 08:35 AM  #5 
Global Moderator Joined: Dec 2006 Posts: 21,124 Thanks: 2332 
p = √(r²  q²) suffices. If q = 9.3 and r = 11.4, what value does that give you for p (to 1 d.p.)? 
May 21st, 2019, 12:42 PM  #6 
Senior Member Joined: Mar 2019 From: TTF area Posts: 180 Thanks: 1 
p≈6.59 so p= about 6.6 is there a good formula to use for this? Last edited by helpmeddddd; May 21st, 2019 at 12:53 PM. 
May 21st, 2019, 02:47 PM  #7 
Senior Member Joined: Oct 2018 From: USA Posts: 102 Thanks: 77 Math Focus: Algebraic Geometry  
May 21st, 2019, 04:23 PM  #8 
Global Moderator Joined: Dec 2006 Posts: 21,124 Thanks: 2332  
May 21st, 2019, 04:29 PM  #9  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1039  Quote:
If so, seems to be something wrong with your teacher...  
May 21st, 2019, 08:43 PM  #10  
Senior Member Joined: Mar 2019 From: TTF area Posts: 180 Thanks: 1  Quote:  

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