May 5th, 2019, 11:20 AM  #1 
Newbie Joined: Oct 2017 From: Egypt Posts: 15 Thanks: 0  I found new solution for this problem hi every on for omega "cubic roots for 1" what do you think ? 
May 5th, 2019, 01:31 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,834 Thanks: 733 
I think you need to clarify what you are doing.

May 6th, 2019, 12:15 PM  #4 
Newbie Joined: Oct 2017 From: Egypt Posts: 15 Thanks: 0 
If you don't understand anything, see video or reply to me.
Last edited by skipjack; May 6th, 2019 at 01:14 PM. 
May 6th, 2019, 12:42 PM  #5 
Global Moderator Joined: May 2007 Posts: 6,834 Thanks: 733 
Small print is an obstacle.

May 6th, 2019, 12:44 PM  #6 
Newbie Joined: Oct 2017 From: Egypt Posts: 15 Thanks: 0 
Hmm, I can't type omega or power in your forum?? You can save them and zoom. Or open in new tape and zoom. What is your opinion? Last edited by skipjack; May 6th, 2019 at 01:15 PM. 
May 6th, 2019, 01:05 PM  #7 
Newbie Joined: Oct 2017 From: Egypt Posts: 15 Thanks: 0 
Please if you like my explanation hit like

May 6th, 2019, 01:14 PM  #8 
Global Moderator Joined: Dec 2006 Posts: 21,028 Thanks: 2259 
As ω + ω² = 1, (1  ω)(1  ω²) = 1  ω  ω² + ω³ = 2 + 1 = 3. Similarly, each successive pair of factors has product 3. 
May 6th, 2019, 02:08 PM  #9 
Newbie Joined: Oct 2017 From: Egypt Posts: 15 Thanks: 0 
But why you are taking successive pairs? I think 2n means the number of our factors. Last edited by skipjack; May 6th, 2019 at 03:38 PM. 
May 6th, 2019, 03:39 PM  #10 
Global Moderator Joined: Dec 2006 Posts: 21,028 Thanks: 2259 
As there are 2n factors, there are n pairs of factors. I used successive pairs of factors because each such pair has product 3. 

Tags 
(1ω)(1ω^2), cube roots of unity, cubic roots of unity, problem, yahia kamal 
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