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May 6th, 2019, 04:14 PM   #11
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Okay, but what if the given was only three brackets?
59934030_653367038444064_1692238877223288832_n.jpg

Last edited by yoyo145; May 6th, 2019 at 04:42 PM.
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May 6th, 2019, 04:54 PM   #12
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If the number of factors is odd, the right-hand side will need to involve ω.
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May 6th, 2019, 04:56 PM   #13
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Quote:
Originally Posted by skipjack View Post
If the number of factors is odd, the right-hand side will need to involve ω.
The number of factors is even: 2n

Last edited by skipjack; May 7th, 2019 at 02:28 AM.
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May 7th, 2019, 02:27 AM   #14
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I took "only three brackets" to mean "only three factors", which won't arise (because 2n is even).
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May 7th, 2019, 02:37 AM   #15
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Quote:
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I took "only three brackets" to mean "only three factors", which won't arise (because 2n is even).
can you solve the new problem and explain what do you mean ?
prove that:
59934030_653367038444064_1692238877223288832_n.jpg
=1

Last edited by yoyo145; May 7th, 2019 at 02:55 AM.
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May 7th, 2019, 03:01 AM   #16
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What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work?
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May 7th, 2019, 03:20 AM   #17
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Quote:
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What new problem? For problem (8), consider the factors in successive pairs, as already described. Can you try it for yourself and post your work?
Okay, but really I don't understand why 2n factors means successive pairs. When I read it, I think the question mean to 8 factor or to 10 factors.

Last edited by skipjack; May 7th, 2019 at 06:47 AM.
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May 7th, 2019, 06:57 AM   #18
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The question doesn't specify successive pairs. I suggested successive pairs because that's a convenient way to find the product.
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May 7th, 2019, 07:13 AM   #19
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So your answer is not general because if you get three factors we will not figure out the right answer.

Please check my proof.

Last edited by skipjack; May 7th, 2019 at 07:18 AM.
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May 7th, 2019, 07:17 AM   #20
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There can't be just three factors because it is stated that there are 2n factors.
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