March 13th, 2013, 10:30 AM  #1 
Newbie Joined: Mar 2013 Posts: 1 Thanks: 0  congruence
Hello everyone, My task is to solve this: My attempt to solve: so I can reduce so I can reduce for some are different, so no solution exist. I'm not sure what's next but I can use from first to third congruence: I know that so I can reduce to: so what's next, what is the answer? 
March 13th, 2013, 02:30 PM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,932 Thanks: 1126 Math Focus: Elementary mathematics and beyond  Re: congruence
2x ? 42 (mod 10) ?

March 13th, 2013, 02:38 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,472 Thanks: 2039 
As 412, but not 42, has no solutions.


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