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March 13th, 2013, 10:30 AM   #1
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Hello everyone,
My task is to solve this:

My attempt to solve:
so I can reduce so I can reduce for some

are different, so no solution exist. I'm not sure what's next but I can use from first to third congruence:
I know that so I can reduce to: so what's next, what is the answer?
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March 13th, 2013, 02:30 PM   #2
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Re: congruence

2x ? 42 (mod 10) ?
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March 13th, 2013, 02:38 PM   #3
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As 4|12, but not 42, has no solutions.
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