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FindIf x(y+z)=39, y(z+x)=60, z(y+x)=63 Find x^2+y^2+z^2 |

eq(1)+eq(2)-eq(3) gives xy=12 . Same thing is for yz and xz . |

xy + xz + 00 = 39 xy + 00 + yz = 60 00 + xz + yz = 63 3 equations, 3 unknowns...so solve for each unknown. Suggest you use elimination process... |

The given equations are linear in xy, xz and yz, with solution (xy, xz, yz) = (18, 21, 9). Hence x² = (xy)(xz)/(yz) = 9, and, similarly, y² = 36 and z² = 49, so x² + y² + z² = 94. |

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