
Algebra PreAlgebra and Basic Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
January 20th, 2019, 02:04 AM  #1 
Newbie Joined: Jan 2019 From: Europe Posts: 3 Thanks: 0  Prove of an inequation with absolute values
Hello, how can I prove that if 3f(x)=2x+sin(f(x)) for all x€R, then f(x)<=x for all x€R? 
January 20th, 2019, 04:02 AM  #2 
Senior Member Joined: Dec 2015 From: somewhere Posts: 509 Thanks: 79 
Hint: $\displaystyle \sin f(x) \leq f(x)$ .


Tags 
absolute, inequation, prove, values 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Absolute inequationx^2x+11 < x  IamRetarded  Calculus  3  February 8th, 2017 02:19 PM 
Absolute Value Inequality with Absolute Values on Both Sides  shiseonji  Algebra  2  September 24th, 2013 08:36 AM 
Prove inequation  thehurtlooker  Algebra  3  April 14th, 2013 06:41 AM 
Prove inequation  thehurtlooker  Algebra  3  April 10th, 2013 07:24 PM 
absolute value inequation  mikeasaf  Algebra  3  November 19th, 2011 08:03 AM 