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 January 20th, 2019, 02:04 AM #1 Newbie   Joined: Jan 2019 From: Europe Posts: 3 Thanks: 0 Prove of an inequation with absolute values Hello, how can I prove that if 3f(x)=2x+sin(f(x)) for all x€R, then |f(x)|<=|x| for all x€R?
 January 20th, 2019, 04:02 AM #2 Senior Member   Joined: Dec 2015 From: somewhere Posts: 509 Thanks: 79 Hint: $\displaystyle \sin f(x) \leq |f(x)|$ .

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