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January 20th, 2019, 02:04 AM   #1
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Prove of an inequation with absolute values

Hello,

how can I prove that if 3f(x)=2x+sin(f(x)) for all x€R, then |f(x)|<=|x| for all x€R?
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January 20th, 2019, 04:02 AM   #2
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Hint: $\displaystyle \sin f(x) \leq |f(x)|$ .
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