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January 9th, 2019, 01:22 PM   #1
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Algebra Word Problem.

In New York City, a taxi ride costs 2 dollars plus 0.30 cents per 1/5 mile and 20 cents per minute stopped in traffic. Due to traffic, Glenda's taxi took 20 min to complete what is usually a 10 min drive. If she is charged 13 dollars for the ride, how far did Glenda travel?

2 + 0.3 (miles/(1/5)) + 0.2t = 13
I tried the above equation, but it has two variables and I can't solve it. I'm not sure there is supposed to be two variables.


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Last edited by skipjack; January 9th, 2019 at 07:03 PM.
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January 9th, 2019, 03:01 PM   #2
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It it's usually a 10 minute drive, then I guess we assume that a 20 minute drive means they stopped in traffic for 10 minutes. Terrible assumption that the nominal drive has no stops, but that's what we'll go with.

So the part of the fare due to stopped in traffic is $(0.2)(10) = \$2$

So the fare due to mileage is $13 - 2 - 2 = \$9$

$9 = (0.3)(5)m = 1.5m$

$\displaystyle m = \frac{9}{1.5} = 6~\text{miles}$
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Last edited by skipjack; January 9th, 2019 at 07:08 PM.
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January 9th, 2019, 03:19 PM   #3
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Yes, this is the answer my text has.

"Terrible assumption that the nominal drive has no stops, but that's what we'll go with." Confused me too.

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Last edited by skipjack; January 9th, 2019 at 07:08 PM.
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