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January 9th, 2019, 12:22 PM  #1 
Newbie Joined: Dec 2018 From: NY Posts: 5 Thanks: 0  Algebra Word Problem.
In New York City, a taxi ride costs 2 dollars plus 0.30 cents per 1/5 mile and 20 cents per minute stopped in traffic. Due to traffic, Glenda's taxi took 20 min to complete what is usually a 10 min drive. If she is charged 13 dollars for the ride, how far did Glenda travel? 2 + 0.3 (miles/(1/5)) + 0.2t = 13 I tried the above equation, but it has two variables and I can't solve it. I'm not sure there is supposed to be two variables. Thanks. Last edited by skipjack; January 9th, 2019 at 06:03 PM. 
January 9th, 2019, 02:01 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,553 Thanks: 1403 
It it's usually a 10 minute drive, then I guess we assume that a 20 minute drive means they stopped in traffic for 10 minutes. Terrible assumption that the nominal drive has no stops, but that's what we'll go with. So the part of the fare due to stopped in traffic is $(0.2)(10) = \$2$ So the fare due to mileage is $13  2  2 = \$9$ $9 = (0.3)(5)m = 1.5m$ $\displaystyle m = \frac{9}{1.5} = 6~\text{miles}$ Last edited by skipjack; January 9th, 2019 at 06:08 PM. 
January 9th, 2019, 02:19 PM  #3 
Newbie Joined: Dec 2018 From: NY Posts: 5 Thanks: 0 
Yes, this is the answer my text has. "Terrible assumption that the nominal drive has no stops, but that's what we'll go with." Confused me too. Thanks Last edited by skipjack; January 9th, 2019 at 06:08 PM. 

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