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 January 6th, 2019, 05:46 AM #1 Member   Joined: Aug 2018 From: Nigeria Posts: 73 Thanks: 2 Sequence&Series Given the exponential sequence 3, 9/2, 27/4, ..., find the number of terms for its sum to be greater than 368. Last edited by skipjack; January 6th, 2019 at 01:09 PM.
 January 6th, 2019, 01:06 PM #2 Global Moderator   Joined: Dec 2006 Posts: 20,972 Thanks: 2222 Use a calculator to find the total of, say, the first 12 terms. What do you get? The first 9 terms total $224 \frac{169}{256}$.
 January 6th, 2019, 07:07 PM #3 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 a = 3 (1st term), m = 3/2 (common multiplier) Assume sum = 368 a(m^n - 1) / (m - 1) = 368 n = ~10.192 So 11.

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