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 Algebra Pre-Algebra and Basic Algebra Math Forum

 December 18th, 2018, 07:08 AM #1 Member   Joined: Aug 2016 From: Romania Posts: 32 Thanks: 1 Exponential equation problem I have the following equation 2^x+2^(-x)=3 4^x+4^(-x)=? The solution is 7, but I don't know how to reach that answer. Can anyone help me? Last edited by skipjack; December 18th, 2018 at 02:20 PM. December 18th, 2018, 07:38 AM #2 Senior Member   Joined: Sep 2015 From: USA Posts: 2,552 Thanks: 1402 $2^x + 2^{-x} = 3$ \begin{align*} &9 = \\ &(2^x+2^{-x})^2 = \\ &2^{2x}+2+2^{-2x} = \\ &4^x + 2 + 4^{-x}\\ &4^x + 4^{-x} = 7 \end{align*} Thanks from skeeter Tags equation, exponential, problem Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post ducanhle Algebra 2 September 7th, 2018 12:07 PM Myriam Algebra 4 April 7th, 2018 03:00 PM panky Algebra 2 August 17th, 2012 05:17 PM davidonut Algebra 2 July 9th, 2011 01:21 AM Jeet Algebra 18 September 21st, 2010 02:14 AM

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