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December 12th, 2018, 03:29 PM  #1 
Newbie Joined: Dec 2018 From: New Zealand Posts: 1 Thanks: 0  Polynomial help please
Not sure where to start.

December 12th, 2018, 04:46 PM  #2 
Math Team Joined: May 2013 From: The Astral plane Posts: 1,980 Thanks: 789 Math Focus: Wibbly wobbly timeywimey stuff.  
December 12th, 2018, 07:58 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,105 Thanks: 1907 
As $p(x)$ has no term in $x^3$, $p(x) = (x^2 + x + 2)(x^2  x + a/2)$. As it also has no term in $x$, $a/2  2 = 0$, and so $a = 4$. Hence $p(x) = (x^2 + x + 2)(x^2  x + 2)$. 
January 3rd, 2019, 07:52 PM  #4 
Newbie Joined: Jan 2019 From: Dayton Posts: 2 Thanks: 0 Math Focus: algebra, calculus, numerical methods  Do long division  you will get a remainder of a4. Given that x^2+x+2 is a factor, remainder does not exist. For it to not exist, a needs to be equal to 4. Check out the link.
Last edited by skipjack; January 3rd, 2019 at 09:03 PM. 

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