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 October 8th, 2018, 10:43 AM #1 Senior Member   Joined: Apr 2017 From: New York Posts: 106 Thanks: 6 rational expression simplification Hi everyone, I couldn't do this: (x^2-y^2-4y-4) / (x^2-y^2-4y+4) any idea?
 October 8th, 2018, 12:52 PM #2 Global Moderator   Joined: May 2007 Posts: 6,610 Thanks: 617 Add and subtract 8 to the numerator. Get 1 +8/denominator.
 October 8th, 2018, 03:56 PM #3 Senior Member   Joined: Apr 2017 From: New York Posts: 106 Thanks: 6 Did you mean 1 - 8/denominator? because if I add and subtract 8 what I get on numerator is exactly the same as denominator -8
October 8th, 2018, 06:12 PM   #4
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Quote:
 Originally Posted by Leonardox Hi everyone, I couldn't do this: (x^2-y^2-4y-4) / (x^2-y^2-4y+4) any idea?
The idea suggested to you is:

$\dfrac{z - a}{z + a} = \dfrac{z - a + 0}{z + a} = \dfrac{z - a + 2a - 2a}{z + a} = \dfrac{z + a - 2a}{z + a} = \dfrac{z + a}{z + a} - \dfrac{2a}{z + a}= WHAT?$

What is the relevance of this general idea to your specific problem?

Last edited by JeffM1; October 8th, 2018 at 06:21 PM.

October 9th, 2018, 01:22 PM   #5
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Quote:
 Originally Posted by Leonardox Did you mean 1 - 8/denominator? because if I add and subtract 8 what I get on numerator is exactly the same as denominator -8
You are right. I get sloppy at times.

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