September 29th, 2018, 09:26 AM  #1 
Newbie Joined: Jul 2018 From: Germany Posts: 20 Thanks: 1  fundamental subtraction question
I have: sin(ec) c=e+a now is it: sin(e  e+a) or sin(e + 1*(e+a)) = sin(e  e a) it has to be the latter right? 
September 29th, 2018, 09:34 AM  #2 
Senior Member Joined: Jun 2015 From: England Posts: 887 Thanks: 266 
Yes the last is correct, but you don't need the 1 multiplier. Just use brackets. Sin(ec) where c = [e+a] is Sin(e[e+a]) = sin(ee+a) = sin(a) 
September 30th, 2018, 11:16 AM  #3 
Senior Member Joined: Jun 2015 From: England Posts: 887 Thanks: 266 
Oops I really don't deserve that thanks as I posted the wrong thing. But it was a good job it came up since I can now apologise and correct my mistake. Sin(e[e+a]) = sin(eea) = sin(a) Not Sin(e[e+a]) = sin(ee+a) = sin(a) as I originally wrote. It is very important to realise that the minus sign before a bracket changes every sign in the bracket. 
September 30th, 2018, 02:44 PM  #4 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,302 Thanks: 935  
September 30th, 2018, 04:19 PM  #5 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,717 Thanks: 597 Math Focus: Yet to find out.  
September 30th, 2018, 05:16 PM  #6 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,302 Thanks: 935 
It's still "whoops" out here !

September 30th, 2018, 05:44 PM  #7 
Senior Member Joined: May 2016 From: USA Posts: 1,148 Thanks: 479  
September 30th, 2018, 05:49 PM  #8 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,302 Thanks: 935 
...plus they drink "spots of tea"....

September 30th, 2018, 05:52 PM  #9 
Senior Member Joined: May 2016 From: USA Posts: 1,148 Thanks: 479  
September 30th, 2018, 06:01 PM  #10 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,302 Thanks: 935 
Oh ya...google "caribou whiskey".... or: Caribou noun 1.Canadian a mixed drink containing wine and grain alcohol Last edited by Denis; September 30th, 2018 at 06:05 PM. 

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