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September 21st, 2018, 11:47 AM  #1 
Newbie Joined: Aug 2018 From: Utah Posts: 6 Thanks: 0  Checking for Errors in Textbook
I have beat my head over this question over and over, and I still can't see how the book gets its answer. I would like you guys to see what you get before I send a note to the author. k × 3^2 − ( j + k ) − 5 ; use j = 4 , k = 5 I get 31 for this, but the book says 36. My guess is that they failed to calculate the "  5 " at the end. Last edited by skipjack; September 21st, 2018 at 08:32 PM. 
September 21st, 2018, 11:59 AM  #2 
Senior Member Joined: May 2016 From: USA Posts: 1,306 Thanks: 549 
$j = 4 \text { and } k = 5 \implies k * 3^2  (j + k)  5=$ $5 * 3^2  (4 + 5)  5 = 5 * 3^2  9  5 = = 5 * 9  14 = 45  14 = 31.$ 

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