My Math Forum simple maths problem driving me nuts.

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 September 4th, 2018, 08:49 PM #1 Newbie   Joined: Sep 2018 From: toronto Posts: 2 Thanks: 0 simple maths problem driving me nuts. if 100x = 1.1 and 0x=0.9 what is the value of x? I need the answer to be written out into a formula as I'm trying to code an algorithm into a sliding function that increases a number by 10% when it's at 100, and decreases it by 10% when at 0. Last edited by skipjack; September 4th, 2018 at 09:42 PM.
 September 4th, 2018, 09:48 PM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,311 Thanks: 1223 $0x = 0$ for all $x$ $10\% \text{ of }0 \text{ is }0$ maybe rethink exactly what it is you are trying to do.
 September 4th, 2018, 09:58 PM #3 Global Moderator   Joined: Dec 2006 Posts: 20,285 Thanks: 1967 Would an increase of (0.2x - 10)% be okay? That's -10% for x = 0 and 10% for x = 100. It would change the number y to (0.002x + 0.9)y, which is 0.9y for x = 0 and 1.1y for x = 100.
 September 5th, 2018, 07:41 AM #4 Newbie   Joined: Sep 2018 From: toronto Posts: 2 Thanks: 0 thank you so much skipjack! could you point me towards where I can learn more about these kind of problems. I imagine you did: y= the difference between the two points y= 1.1-0.9 y= 0.2 x= a number between 0 and 100 so (yx-10)%, but how did you get the -10?
 September 5th, 2018, 10:08 AM #5 Global Moderator   Joined: Dec 2006 Posts: 20,285 Thanks: 1967 I didn't say (yx-10)%. The change is (0.2x - 10)% for any y. Putting x = 0 gives -10%, and putting x = 100 gives 10%, as requested.

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