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June 28th, 2018, 11:23 PM  #1 
Senior Member Joined: Aug 2014 From: India Posts: 343 Thanks: 1  how to compare X and Y values?
Questions: 8X^2 + 34X + 21 = 0 6Y^2 + 7Y + 2 = 0 Solutions: X values of first equation: 7/2 or 3/4 Y values of second equation: 1/2 or 2/3 Answer is X < Y Here X and Y got 2 values, how to compare X and Y values? Last edited by Ganesh Ujwal; June 29th, 2018 at 12:07 AM. 
June 29th, 2018, 12:12 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,464 Thanks: 2038 
As both values for X are less than both values for Y, X < Y for whichever values are compared.


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