
Algebra PreAlgebra and Basic Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
June 28th, 2018, 02:11 AM  #1 
Member Joined: Aug 2017 From: India Posts: 50 Thanks: 2  Infinite solutions problem
I am trying to solve following problem. I am trying to find x,y,z in terms of $\displaystyle \lambda$. And then equating the resultant equation to 0. Am I correct?
Last edited by skipjack; June 28th, 2018 at 07:05 AM. 
June 28th, 2018, 07:46 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,262 Thanks: 1958 
No, because "equating an equation to zero" doesn't make sense. What did you equate to zero?

June 28th, 2018, 08:59 AM  #3 
Member Joined: Aug 2017 From: India Posts: 50 Thanks: 2 
After replacing y and z, finally I arrived at the following equation if I hopefully did not a mistake $\displaystyle x*\lambda*(\lambda^2+4*\lambda3)=0 $ So I find that there are 3 solutions, with one of them being 0. Am I correct? Please advise. Last edited by skipjack; June 28th, 2018 at 02:22 PM. 
June 28th, 2018, 02:25 PM  #4 
Global Moderator Joined: May 2007 Posts: 6,680 Thanks: 658 
Calculate the determinant: $\lambda^3+4\lambda36=0$. This has only 1 real root, which is the desired solution.

June 28th, 2018, 02:27 PM  #5 
Global Moderator Joined: Dec 2006 Posts: 20,262 Thanks: 1958  
June 28th, 2018, 05:27 PM  #6 
Senior Member Joined: Feb 2010 Posts: 702 Thanks: 137 
These three equations represent three planes in 3 dimensional space. To have an infinite number of solutions these three planes must either be coincident or must intersect in a common line. The planes cannot be coincident since the attitude numbers (coefficients of x,y,z) are not proportional. To have a common line, the three planes must have two points in common. (0,0,0) is common to all three so all you need is one more. I think that $\displaystyle \left( \dfrac{\lambda^2+4\lambda8}{2},\lambda+2,8\lambda \right)$ is also common to all three planes (although I'm not sure of my arithmetic). If I'm correct then it appears that any value of $\displaystyle \lambda$ would make a line with (0,0,0) that produces an infinite number of solutions. Can someone check this? 
June 28th, 2018, 08:49 PM  #7 
Global Moderator Joined: Dec 2006 Posts: 20,262 Thanks: 1958 
It's incorrect.

June 29th, 2018, 08:50 AM  #8  
Math Team Joined: Dec 2013 From: Colombia Posts: 7,598 Thanks: 2583 Math Focus: Mainly analysis and algebra  Quote:
Unfortunately, the quadratic has no real roots. Last edited by v8archie; June 29th, 2018 at 08:52 AM.  
June 29th, 2018, 10:54 AM  #9 
Global Moderator Joined: Dec 2006 Posts: 20,262 Thanks: 1958 
The correct equation doesn't factorize that simply.

June 29th, 2018, 12:01 PM  #10 
Member Joined: Aug 2017 From: India Posts: 50 Thanks: 2 
This is the attempt I have done. The final equation is $\displaystyle x(\lambda^3+4\lambda40)=0; $ I am not sure why I got a different equation last time. Sorry if the attachments are not clear. Next time, I will try to use math editor. Please advise whether I am correct. Last edited by skipjack; June 29th, 2018 at 10:05 PM. 

Tags 
infinite, problem, solutions 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
echelon method expressing with infinite solutions  blimper  Linear Algebra  4  August 30th, 2016 07:53 PM 
How can anybody insist that this set of equations have infinite number of solutions?  king.oslo  Linear Algebra  4  April 6th, 2014 05:47 PM 
Matrix with infinite solutions  84grandmarquis  Linear Algebra  2  September 29th, 2013 02:59 PM 
Problem with infinite solutions  EduXx  Computer Science  2  October 7th, 2012 04:10 PM 
Matrix with infinite solutions  84grandmarquis  Algebra  0  December 31st, 1969 04:00 PM 