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June 26th, 2018, 02:40 AM   #1
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How to find logarithm of a number having negative characteristic.

Hi,
can anybody help me find logarithm of a number having negative characteristic?
For example, log(0.00462).
Any help would be highly appreciated.
Thanks.

Last edited by skipjack; June 26th, 2018 at 03:11 PM.
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June 26th, 2018, 05:06 AM   #2
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$\log_{10}(10^k x) = \log(x) + k$

so for example I assume you can find $y=\log(4.62)$ where in this case $k=-3$

then

$\log(0.00462) = y - 3$
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June 26th, 2018, 08:40 AM   #3
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I don't understand $ and euro currency sign. For which purpose they are used here, I don't understand your answer. Thanks for your reply. though. I can find all kinds of logs, but not logs having negative characteristics, e.g. log(0.00462) and log(.5143). It's easily found using a calculator, but I want to find it manually.
Any help would be highly appreciated.
Thanks.

Last edited by skipjack; June 26th, 2018 at 03:08 PM.
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June 26th, 2018, 09:04 AM   #4
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Is that any better? Your browser isn't rendering the LaTex.
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June 26th, 2018, 09:33 AM   #5
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Simply tell me how log(0.00462)=-2.3354 and log(.5143)=-.288791
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June 26th, 2018, 09:57 AM   #6
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Quote:
Originally Posted by rewt View Post
Simply tell me how log(0.00462)=-2.3354 and log(.5143)=-.288791
Just do what Romsek said.

Find log(4.62) and then subtract 3.
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June 26th, 2018, 10:25 AM   #7
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Now I understand. I have solved other problems like this. Thanks.

Last edited by skipjack; June 26th, 2018 at 03:11 PM.
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