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 Algebra Pre-Algebra and Basic Algebra Math Forum

 June 17th, 2018, 09:11 AM #2 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,955 Thanks: 988 What do you understand? Can you solve something simpler, like: 5x + 12 = 3x + 20 Can you solve that for x ?
 June 17th, 2018, 09:36 AM #3 Global Moderator   Joined: Dec 2006 Posts: 20,274 Thanks: 1959 The equations f(x) = 3x - 2x - 1 g(x) = x² - 1 h(x) = f(x) + g(x) are to be treated as definitions of f(x) and g(x) in terms of x, and of h(x) in terms of f(x) and g(x). Note that "3x - 2x - 1", if that was typed correctly, can be simplified to x - 1. Note that terms such as "3x" mean "3(x)" (the product of 3 and x), but "f(x)" doesn't mean the product of f and x. To evaluate f(-1), one replaces each "x" in "f(x) = 3x - 2x - 1" with "-1". Doing that gives f(-1) = 3(-1) - 2(-1) - 1. The right-hand side evaluates to -6. The above should help with doing parts b and c of the question.
 June 17th, 2018, 10:45 AM #4 Senior Member   Joined: Aug 2012 Posts: 2,156 Thanks: 630 OP, is f(x)=3x-2x-1 supposed to be perhaps $f(x)=3x^2-2x-1$? Otherwise 3x - 2x = x.

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