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June 17th, 2018, 01:50 AM  #1 
Newbie Joined: Jun 2018 From: Philippines Posts: 1 Thanks: 0  Please help me, as I'm really bad at math...
Let f(x)=3x2x1 g(x)=x²1 h(x)=f(x)+g(x) a. (f g) (x) b. f(1) ⋅ g(2) ⋅ h(0) c. g(x)/f(x) d. h(x1) e. f(3)+g(2) Please help me. I really don't understand any of these; I'm really really bad at math. It's not that I don't listen, because I do listen, but I just don't understand when my teacher explains, and it's not my teachers fault, I'm just really really fucking dumb, I just copied what my teacher wrote on the board. Please help me with steps too, thanks... Last edited by skipjack; June 17th, 2018 at 08:21 AM. 
June 17th, 2018, 08:11 AM  #2 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,771 Thanks: 862 
What do you understand? Can you solve something simpler, like: 5x + 12 = 3x + 20 Can you solve that for x ? 
June 17th, 2018, 08:36 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 19,191 Thanks: 1649 
The equations f(x) = 3x  2x  1 g(x) = x²  1 h(x) = f(x) + g(x) are to be treated as definitions of f(x) and g(x) in terms of x, and of h(x) in terms of f(x) and g(x). Note that "3x  2x  1", if that was typed correctly, can be simplified to x  1. Note that terms such as "3x" mean "3(x)" (the product of 3 and x), but "f(x)" doesn't mean the product of f and x. To evaluate f(1), one replaces each "x" in "f(x) = 3x  2x  1" with "1". Doing that gives f(1) = 3(1)  2(1)  1. The righthand side evaluates to 6. The above should help with doing parts b and c of the question. 
June 17th, 2018, 09:45 AM  #4 
Senior Member Joined: Aug 2012 Posts: 1,960 Thanks: 547 
OP, is f(x)=3x2x1 supposed to be perhaps $f(x)=3x^22x1$? Otherwise 3x  2x = x.


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