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June 16th, 2018, 03:57 AM  #11 
Member Joined: Aug 2017 From: India Posts: 45 Thanks: 2 
I think E should be the answer.

June 16th, 2018, 10:45 AM  #12 
Global Moderator Joined: Dec 2006 Posts: 19,547 Thanks: 1753 
It is if "these" means "the above".

June 16th, 2018, 01:30 PM  #13 
Senior Member Joined: Sep 2016 From: USA Posts: 444 Thanks: 254 Math Focus: Dynamical systems, analytic function theory, numerics 
I don't see any justification so far that (B) is incorrect. Looking at solutions for $x = \frac{1}{x1}$ is not enough. (B) is equivalent to asserting there are no periodic orbits for the mapping given by $y$. I would look at the derivative of $y$. 

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