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June 16th, 2018, 04:57 AM   #11
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I think E should be the answer.
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June 16th, 2018, 11:45 AM   #12
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It is if "these" means "the above".
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June 16th, 2018, 02:30 PM   #13
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I don't see any justification so far that (B) is incorrect. Looking at solutions for $x = \frac{1}{x-1}$ is not enough. (B) is equivalent to asserting there are no periodic orbits for the mapping given by $y$.

I would look at the derivative of $y$.
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