
Algebra PreAlgebra and Basic Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
May 28th, 2018, 02:11 PM  #1 
Newbie Joined: Mar 2017 From: Norway Posts: 8 Thanks: 0  Please help me to solve this quartic equation.
Please help me to solve this quartic equation. $(6x+7)^2(3x+4)(x+1)=6$ which is the same as: $108x^4+504x^3+879x^2+679x+190=0$ 
May 29th, 2018, 01:24 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,295 Thanks: 1686 
The equation is equivalent to $(3x + 5)(3x + 2)(12x^2 + 28x + 19) = 0$. The first two factors can be guessed after plotting the graph of the quartic. The quadratic factor can then be found by division. 

Tags 
equation, quartic, solve 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Help ! roots of quartic equation.  HTsds  Algebra  4  December 17th, 2016 06:47 AM 
Quartic equation with parameter m  goldgold  Algebra  5  December 26th, 2014 05:15 AM 
Quartic Equation  Jopus  Algebra  0  May 23rd, 2014 10:38 AM 
Quartic equation  hoyy1kolko  Algebra  6  October 28th, 2011 12:54 AM 
Quartic equation with complex roots  ally  Algebra  2  July 24th, 2008 11:51 AM 