Algebra Pre-Algebra and Basic Algebra Math Forum

 May 28th, 2018, 03:11 PM #1 Newbie   Joined: Mar 2017 From: Norway Posts: 12 Thanks: 0 Please help me to solve this quartic equation. Please help me to solve this quartic equation. $(6x+7)^2(3x+4)(x+1)=6$ which is the same as: $108x^4+504x^3+879x^2+679x+190=0$
 May 29th, 2018, 02:24 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,098 Thanks: 1905 The equation is equivalent to $(3x + 5)(3x + 2)(12x^2 + 28x + 19) = 0$. The first two factors can be guessed after plotting the graph of the quartic. The quadratic factor can then be found by division.

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