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May 28th, 2018, 02:11 PM  #1 
Newbie Joined: Mar 2017 From: Norway Posts: 12 Thanks: 0  Please help me to solve this quartic equation.
Please help me to solve this quartic equation. $(6x+7)^2(3x+4)(x+1)=6$ which is the same as: $108x^4+504x^3+879x^2+679x+190=0$ 
May 29th, 2018, 01:24 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,712 Thanks: 1806 
The equation is equivalent to $(3x + 5)(3x + 2)(12x^2 + 28x + 19) = 0$. The first two factors can be guessed after plotting the graph of the quartic. The quadratic factor can then be found by division. 

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