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 March 6th, 2013, 01:51 AM #1 Newbie   Joined: Mar 2013 Posts: 12 Thanks: 0 Sequence and Series For positive real numbers a,b,c prove that (a+b)(b+c)(c+a) >= abc
 March 6th, 2013, 01:54 AM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,958 Thanks: 1146 Math Focus: Elementary mathematics and beyond Re: Sequence and Series Expand (a + b)(b + c)(c + a).
March 6th, 2013, 02:45 AM   #3
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Re: Sequence and Series

Quote:
 Originally Posted by greg1313 Expand (a + b)(b + c)(c + a).
No need to. a + b > a, b + c > b, c + a > c, hence (a+b)(b+c)(c+a) > abc.

 March 6th, 2013, 08:22 PM #4 Global Moderator   Joined: Dec 2006 Posts: 20,927 Thanks: 2205 How about a topic title that has some bearing on the problem posted?

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