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July 22nd, 2008, 04:59 PM  #1 
Newbie Joined: Jul 2008 Posts: 10 Thanks: 0  Points of intersection of a circle.
What would the points of intersection of the circle x^2 + ( y  1 )^2 = 25 and y =  7x + 26 be using the system of equations to solve?

July 23rd, 2008, 02:59 AM  #2 
Newbie Joined: Jun 2008 From: New Zealand Posts: 20 Thanks: 0  Re: Points of intersection of a circle.
Substituting into , we have So or When , when , Thus the two points are (3, 5) and (4, 2) 
July 23rd, 2008, 10:49 AM  #3 
Newbie Joined: Jul 2008 Posts: 10 Thanks: 0  Re: Points of intersection of a circle.
Thank you so much. How would i find the length of the chord in radical form for that answer?

July 23rd, 2008, 02:14 PM  #4 
Newbie Joined: Jun 2008 From: New Zealand Posts: 20 Thanks: 0  Re: Points of intersection of a circle.
The length of the chord is the distance between (3, 5) and (4, 2). To find the distance between and , use the following formula: The answer in radical form is 
July 23rd, 2008, 04:11 PM  #5 
Newbie Joined: Jul 2008 Posts: 10 Thanks: 0  Re: Points of intersection of a circle.
Would i do the same kind of a thing to find the distance from the center of the circle to the chord?


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