April 16th, 2018, 09:49 AM  #1 
Newbie Joined: Apr 2018 From: Calgary Posts: 3 Thanks: 0  Solve for x
y=a*(1+(b*m*x))^(1/b) How to solve for x? 
April 16th, 2018, 09:57 AM  #2 
Senior Member Joined: May 2016 From: USA Posts: 989 Thanks: 406 
Why is this in calculus? Here's a start (making certain assumptions on the values of a, b, and m): $y = a(1 + bmx)^{(1/b)} \implies y = \dfrac{a}{\sqrt[b]{1 + bmx}} \implies$ $\sqrt[b]{1 + bmx} = \dfrac{a}{y} \implies WHAT?$ 
April 16th, 2018, 10:13 AM  #3 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,074 Thanks: 794 
y / a = 1 / (1 + bmx)^(1 / b) (1 + bmx)^(1 / b) = a / y Can you finish it? We do not give out full solutions. 
April 16th, 2018, 10:26 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 18,838 Thanks: 1564 
Moved from Calculus to Algebra.

April 16th, 2018, 10:35 AM  #5 
Newbie Joined: Apr 2018 From: Calgary Posts: 3 Thanks: 0 
ok. thanks

April 16th, 2018, 11:17 AM  #6 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,074 Thanks: 794 
Hint: if x^a = y, then x = y^(1 / a)

April 16th, 2018, 02:19 PM  #7 
Newbie Joined: Apr 2018 From: Calgary Posts: 3 Thanks: 0 
x=((((y/a)^(b))1)/bm) Did I get it right? 
April 16th, 2018, 03:24 PM  #8 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,074 Thanks: 794  YES...but you need to bracket the denominator bm: x=((((y/a)^(b))1)/(bm)) You have extra brackets (ok to leave as they are but not required); this is sufficient: x=((y / a)^(b)  1) / (bm) Can be rearranged this way: x = ((a / y)^b  1) / (bm) You can check if correct by using original equation and assigning values to a,b,m,x then calculating y from these values, then seeing if x comes out ok using your "solution equation". Try it; say a=2, b=3, c=4, x=5. See what I mean? 
April 16th, 2018, 03:27 PM  #9 
Global Moderator Joined: Dec 2006 Posts: 18,838 Thanks: 1564 
Nearly... x = ((y/a)^(b)  1)/(bm) has correct use of parentheses, or you could give x = ((a/y)^b  1)/(bm). 

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