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April 13th, 2018, 07:15 PM  #1 
Newbie Joined: Apr 2018 From: Canada Posts: 1 Thanks: 0  Turning Crazy help me please
Hi. I need help with this math problem and it's making me crazy. (9a²3a)/3a+(a+2)(2a+1) I know the answer is: 2a²+2a+3 (seen it on my calculator). But I can't figure out how it goes from this [(9a²3a)/3a+(a+2)(2a+1)] to this [2a²+2a+3]. Can anyone give me the step by step on how to resolve this? Please help me. 
April 13th, 2018, 07:50 PM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 1,847 Thanks: 953 
$\dfrac{9a^2  3a}{3a} = 13a$ so then we have $\begin{align*} &(13a) + (a+2)(2a+1) = \\ \\ &(13a) + (2a^2 + 5a + 2) = \\ \\ &2a^2 + 2a + 3 \end{align*}$ 

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