My Math Forum Turning Crazy help me please

 Algebra Pre-Algebra and Basic Algebra Math Forum

 April 13th, 2018, 07:15 PM #1 Newbie   Joined: Apr 2018 From: Canada Posts: 1 Thanks: 0 Turning Crazy help me please Hi. I need help with this math problem and it's making me crazy. (9a²-3a)/-3a+(a+2)(2a+1) I know the answer is: 2a²+2a+3 (seen it on my calculator). But I can't figure out how it goes from this [(9a²-3a)/-3a+(a+2)(2a+1)] to this [2a²+2a+3]. Can anyone give me the step by step on how to resolve this? Please help me.
 April 13th, 2018, 07:50 PM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,091 Thanks: 1087 $\dfrac{9a^2 - 3a}{-3a} = 1-3a$ so then we have \begin{align*} &(1-3a) + (a+2)(2a+1) = \\ \\ &(1-3a) + (2a^2 + 5a + 2) = \\ \\ &2a^2 + 2a + 3 \end{align*} Thanks from topsquark and Country Boy

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