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April 13th, 2018, 07:15 PM   #1
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Turning Crazy help me please

Hi.
I need help with this math problem and it's making me crazy.

(9a²-3a)/-3a+(a+2)(2a+1) I know the answer is: 2a²+2a+3 (seen it on my calculator).

But I can't figure out how it goes from this [(9a²-3a)/-3a+(a+2)(2a+1)] to this [2a²+2a+3].

Can anyone give me the step by step on how to resolve this?

Please help me.
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April 13th, 2018, 07:50 PM   #2
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$\dfrac{9a^2 - 3a}{-3a} = 1-3a$

so then we have

$\begin{align*}
&(1-3a) + (a+2)(2a+1) = \\ \\

&(1-3a) + (2a^2 + 5a + 2) = \\ \\

&2a^2 + 2a + 3

\end{align*}$
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