User Name Remember Me? Password

 Algebra Pre-Algebra and Basic Algebra Math Forum

 April 12th, 2018, 02:57 AM #1 Banned Camp   Joined: Dec 2017 From: Tel Aviv Posts: 87 Thanks: 3 English What is the name of the thing that mark with ...? mx + n = y n is ... ax^2 + bx + c = y c is ... April 12th, 2018, 04:03 AM #2 Banned Camp   Joined: Dec 2017 From: Tel Aviv Posts: 87 Thanks: 3 And my next question is: What is the difference between this Thing and the Constant Of Integration? Last edited by skipjack; April 12th, 2018 at 04:06 AM. April 12th, 2018, 04:15 AM #3 Global Moderator   Joined: Dec 2006 Posts: 20,370 Thanks: 2007 The technical term is "ellipsis". It isn't related to integration. April 12th, 2018, 04:18 AM #4 Senior Member   Joined: Oct 2009 Posts: 752 Thanks: 257 I think he is refering to the "constant term". April 12th, 2018, 04:20 AM #5 Banned Camp   Joined: Dec 2017 From: Tel Aviv Posts: 87 Thanks: 3 I will it again What is the name of The Thing? mx + n = y n = The Thing ax^2 + bx + c = y c = The Thing. this is a "free number" in my bad English. If integration of f function is (Integral of f) + C what is the difference between c and the "free number"? Is there a connection between them? Last edited by skipjack; April 12th, 2018 at 06:50 AM. April 12th, 2018, 06:58 AM #6 Global Moderator   Joined: Dec 2006 Posts: 20,370 Thanks: 2007 In your equations, n and c appear to be constant terms, as there is nothing to suggest they vary as x varies. When you integrate with respect to x, the C that is added as a constant of integration doesn't vary as x varies, but (in certain circumstances) might vary as something else varies. I haven't come across the term "free number" in this type of context. April 13th, 2018, 01:01 AM   #7
Banned Camp

Joined: Dec 2017
From: Tel Aviv

Posts: 87
Thanks: 3

Quote:
 Originally Posted by skipjack In your equations, n and c appear to be constant terms, as there is nothing to suggest they vary as x varies. When you integrate with respect to x, the C that is added as a constant of integration doesn't vary as x varies, but (in certain circumstances) might vary as something else varies. I haven't come across the term "free number" in this type of context.
What are the circumstances? April 13th, 2018, 01:20 PM   #8
Math Team

Joined: Jan 2015
From: Alabama

Posts: 3,264
Thanks: 902

Quote:
 Originally Posted by policer What are the circumstances?
If you have a "partial differential equation" that has more than one independent variable is one such circumstance.

For example, to solve the differential equation $\displaystyle \frac{\partial^2 z}{\partial x\partial y}= 0$, write it as $\displaystyle \frac{\partial}{\partial x}\left(\frac{\partial z}{\partial y}\right)= 0$. The "anti-derivative", with respect to x, would give $\displaystyle \frac{\partial z}{\partial y}$ plus a "constant". But since this is a partial derivative with respect to x, where we hold y constant, that "constant might in fact be some function of y! That is $\displaystyle \frac{\partial z}{\partial y}+ f(y)$. Now integrating with respect to y, we have $\displaystyle z= F(y)+ "C"$ where F is an anti-derivative of f. And, again, since we differentiated with respect to y, that "C" might be some function of x. If we call that function "G(x)", that becomes $\displaystyle z= F(y)+ G(x)$.

Last edited by skipjack; April 14th, 2018 at 03:48 AM. Tags english Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post shaharhada Complex Analysis 3 April 24th, 2018 10:56 AM Gematria New Users 14 September 16th, 2012 02:20 PM mathbalarka New Users 7 June 20th, 2012 05:35 PM azizlwl Probability and Statistics 11 May 6th, 2012 11:17 PM Ghulam hussain New Users 2 January 21st, 2011 07:07 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top      