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April 11th, 2018, 05:14 AM   #1
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Angles of a triangle with algebra question

So I have tried doing this question using x and y but I keep on coming back to 180=180. How do you solve this?

Please help, thanks!

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April 11th, 2018, 06:15 AM   #2
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$\small\angle\hspace{1px}$PTS + 38$^\circ\!$ = $\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PSQ = $\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PQS = 2$\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PRS = 2$\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PTS
so $\small\angle\hspace{1px}$QSR = 38$^\circ\!$/2 = 19$^\circ\!$.
Thanks from Country Boy and Student2018
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