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April 11th, 2018, 05:14 AM   #1
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Angles of a triangle with algebra question

So I have tried doing this question using x and y but I keep on coming back to 180=180. How do you solve this?

(Question is in attachment)
Attached Images Screen Shot 2018-04-11 at 15.12.39.jpg (11.2 KB, 8 views) April 11th, 2018, 06:15 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,966 Thanks: 2216 $\small\angle\hspace{1px}$PTS + 38$^\circ\!$ = $\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PSQ = $\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PQS = 2$\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PRS = 2$\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PTS so $\small\angle\hspace{1px}$QSR = 38$^\circ\!$/2 = 19$^\circ\!$. Thanks from Country Boy and Student2018 Tags algebra, angles, question, triangle Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Pies Trigonometry 5 March 31st, 2016 04:38 AM Chris A Geometry 6 March 11th, 2015 01:49 AM Imdumb Algebra 10 September 22nd, 2013 05:20 PM Gary147 Algebra 3 January 17th, 2013 06:59 PM bracke Algebra 2 May 10th, 2012 07:23 AM

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