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April 11th, 2018, 05:14 AM  #1 
Member Joined: Apr 2018 From: On Earth Posts: 34 Thanks: 0  Angles of a triangle with algebra question
So I have tried doing this question using x and y but I keep on coming back to 180=180. How do you solve this? Please help, thanks! (Question is in attachment) 
April 11th, 2018, 06:15 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,838 Thanks: 1564 
$\small\angle\hspace{1px}$PTS + 38$^\circ\!$ = $\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PSQ = $\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PQS = 2$\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PRS = 2$\small\angle\hspace{1px}$QSR + $\small\angle\hspace{1px}$PTS so $\small\angle\hspace{1px}$QSR = 38$^\circ\!$/2 = 19$^\circ\!$. 

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algebra, angles, question, triangle 
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