My Math Forum  

Go Back   My Math Forum > High School Math Forum > Algebra

Algebra Pre-Algebra and Basic Algebra Math Forum


Thanks Tree1Thanks
  • 1 Post By topsquark
Reply
 
LinkBack Thread Tools Display Modes
April 7th, 2018, 07:15 AM   #1
Newbie
 
Joined: Apr 2018
From: Israel

Posts: 5
Thanks: 0

Logarithm

Hi,

I don't understand how 0.1 x become 10 here:

log2 (50/3) = 0.1x

= 10 X log2 (50/3)

Here they don't do that
https://www.wolframalpha.com/input/?...%2F3)+%3D+0.1x


Thank in advance.

Last edited by Myriam; April 7th, 2018 at 07:31 AM.
Myriam is offline  
 
April 7th, 2018, 07:45 AM   #2
Math Team
 
topsquark's Avatar
 
Joined: May 2013
From: The Astral plane

Posts: 1,754
Thanks: 701

Math Focus: Wibbly wobbly timey-wimey stuff.
Quote:
Originally Posted by Myriam View Post
Hi,

I don't understand how 0.1 x become 10 here:

log2 (50/3) = 0.1x

= 10 X log2 (50/3)

Here they don't do that
https://www.wolframalpha.com/input/?...%2F3)+%3D+0.1x


Thank in advance.
Your notation seems to be the problem.
$\displaystyle 0.1 x = log_2 \left ( \frac{50}{3} \right )$

$\displaystyle \frac{1}{10} x = log_2 \left ( \frac{50}{3} \right )$

$\displaystyle 10 \cdot \frac{1}{10} x = 10 \cdot log_2 \left ( \frac{50}{3} \right )$

$\displaystyle x = 10 \cdot log_2 \left ( \frac{50}{3} \right )$

Try not to use "X" for multiplication, especially if there is an x already in the problem. 10 log2 (50/3) would work just fine.

-Dan
Thanks from Myriam
topsquark is online now  
Reply

  My Math Forum > High School Math Forum > Algebra

Tags
logarithm



Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
logarithm stoik Algebra 2 March 18th, 2014 08:48 AM
logarithm sachinrajsharma Algebra 4 February 17th, 2013 07:39 AM
Logarithm Algebra 4 February 16th, 2012 05:40 AM
Logarithm Qwertyqwerty Elementary Math 3 October 8th, 2011 02:03 AM
logarithm mathmaniac Abstract Algebra 0 December 31st, 1969 04:00 PM





Copyright © 2018 My Math Forum. All rights reserved.