April 7th, 2018, 07:15 AM  #1 
Newbie Joined: Apr 2018 From: Israel Posts: 5 Thanks: 0  Logarithm
Hi, I don't understand how 0.1 x become 10 here: log2 (50/3) = 0.1x = 10 X log2 (50/3) Here they don't do that https://www.wolframalpha.com/input/?...%2F3)+%3D+0.1x Thank in advance. Last edited by Myriam; April 7th, 2018 at 07:31 AM. 
April 7th, 2018, 07:45 AM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,879 Thanks: 761 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
$\displaystyle 0.1 x = log_2 \left ( \frac{50}{3} \right )$ $\displaystyle \frac{1}{10} x = log_2 \left ( \frac{50}{3} \right )$ $\displaystyle 10 \cdot \frac{1}{10} x = 10 \cdot log_2 \left ( \frac{50}{3} \right )$ $\displaystyle x = 10 \cdot log_2 \left ( \frac{50}{3} \right )$ Try not to use "X" for multiplication, especially if there is an x already in the problem. 10 log2 (50/3) would work just fine. Dan  

Tags 
logarithm 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
logarithm  stoik  Algebra  2  March 18th, 2014 08:48 AM 
logarithm  sachinrajsharma  Algebra  4  February 17th, 2013 07:39 AM 
Logarithm  Algebra  4  February 16th, 2012 05:40 AM  
Logarithm  Qwertyqwerty  Elementary Math  3  October 8th, 2011 02:03 AM 
logarithm  mathmaniac  Abstract Algebra  0  December 31st, 1969 04:00 PM 