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 April 7th, 2018, 07:15 AM #1 Newbie   Joined: Apr 2018 From: Israel Posts: 5 Thanks: 0 Logarithm Hi, I don't understand how 0.1 x become 10 here: log2 (50/3) = 0.1x = 10 X log2 (50/3) Here they don't do that https://www.wolframalpha.com/input/?...%2F3)+%3D+0.1x Thank in advance. Last edited by Myriam; April 7th, 2018 at 07:31 AM.
April 7th, 2018, 07:45 AM   #2
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Quote:
 Originally Posted by Myriam Hi, I don't understand how 0.1 x become 10 here: log2 (50/3) = 0.1x = 10 X log2 (50/3) Here they don't do that https://www.wolframalpha.com/input/?...%2F3)+%3D+0.1x Thank in advance.
Your notation seems to be the problem.
$\displaystyle 0.1 x = log_2 \left ( \frac{50}{3} \right )$

$\displaystyle \frac{1}{10} x = log_2 \left ( \frac{50}{3} \right )$

$\displaystyle 10 \cdot \frac{1}{10} x = 10 \cdot log_2 \left ( \frac{50}{3} \right )$

$\displaystyle x = 10 \cdot log_2 \left ( \frac{50}{3} \right )$

Try not to use "X" for multiplication, especially if there is an x already in the problem. 10 log2 (50/3) would work just fine.

-Dan

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