April 7th, 2018, 08:15 AM  #1 
Newbie Joined: Apr 2018 From: Israel Posts: 5 Thanks: 0  Logarithm
Hi, I don't understand how 0.1 x become 10 here: log2 (50/3) = 0.1x = 10 X log2 (50/3) Here they don't do that https://www.wolframalpha.com/input/?...%2F3)+%3D+0.1x Thank in advance. Last edited by Myriam; April 7th, 2018 at 08:31 AM. 
April 7th, 2018, 08:45 AM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,915 Thanks: 774 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
$\displaystyle 0.1 x = log_2 \left ( \frac{50}{3} \right )$ $\displaystyle \frac{1}{10} x = log_2 \left ( \frac{50}{3} \right )$ $\displaystyle 10 \cdot \frac{1}{10} x = 10 \cdot log_2 \left ( \frac{50}{3} \right )$ $\displaystyle x = 10 \cdot log_2 \left ( \frac{50}{3} \right )$ Try not to use "X" for multiplication, especially if there is an x already in the problem. 10 log2 (50/3) would work just fine. Dan  

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