Algebra Pre-Algebra and Basic Algebra Math Forum

 March 31st, 2018, 04:32 AM #1 Newbie   Joined: Mar 2018 From: Canada Posts: 14 Thanks: 0 Fractions , linear-algebra! Hi everyone, I’m quite new here, so please bare with me! I’m stuck on a a problem and it’s being consuming my entire day! The problem is the following Subtract: x / (x-2).( x+4) from -2 / x^2+2x-8 There are four possible answeres given to me on this problem. They might all be correct or maybe just one of them! a) -(x+2) / x^2 + 2x - 8 B) -2-x / x^2+2x -8 C) -2-x / (x-2)(x+4) D) -x-2 / (x-2)(x+4) I do realize that the denominators are the same, but I’m having trouble figuring out wich options are actually correct( if more than one). When I try calculating the numerators, with any of the options given ( by substituting x for a given number, all the numerators from the possible answers give me the same result! This leads me to believe that all answers are correct. If I’m wrong, it would be great to understand why! Thank you so much in advance !! Last edited by Brunob; March 31st, 2018 at 04:36 AM. March 31st, 2018, 05:23 AM   #2
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Quote:
 Originally Posted by Brunob Subtract: x / (x-2).( x+4) from -2 / x^2+2x-8 NOTE: Brackets required: Subtract: x / ((x-2).( x+4)) from -2 / (x^2+2x-8 )
Let u = x^2 + 2x - 8 = (x-2)(x+4)

-2/u - x/u = (-2 - x)/u = -(x + 2)/u

HOKAY? March 31st, 2018, 05:37 AM #3 Newbie   Joined: Mar 2018 From: Canada Posts: 14 Thanks: 0 Thanks!! I think I got what you mean. So there are 3 correct answers. Saying u = (x-2)(x+4)=x^2+2x-8 So -(x+2)/ u is correct -2-x/u is also correct ( that would be B and C) I’m just not sure why -x-2/u isn’t a correct answer? It does seem to me that it is correct as I would get the same value from others if I put a number for X. Do you mind explaining it to me? Thank u soooo much! March 31st, 2018, 05:59 AM   #4
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Quote:
 Originally Posted by Brunob I’m just not sure why -x-2/u isn’t a correct answer?
Isn't that (-x-2)/u ?

If so, then they are ALL correct!

Check by assigning a value to x; say x=10; all 4 choices = -.2

NOTE: make SURE you understand the importance
of proper BRACKETING.

Last edited by Denis; March 31st, 2018 at 06:10 AM. Reason: Add NOTE March 31st, 2018, 06:11 AM #5 Newbie   Joined: Mar 2018 From: Canada Posts: 14 Thanks: 0 Perfect! Great! Thank you so much! That’s what I’ve thought!!! Rgds, Bruno March 31st, 2018, 06:18 AM #6 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1039 To end this weirdness: do you UNDERSTAND what I mean with "importance of proper bracketing"? April 2nd, 2018, 04:24 PM #7 Newbie   Joined: Mar 2018 From: Canada Posts: 14 Thanks: 0 I do!! Thank you very much April 4th, 2018, 05:16 AM #8 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 With regard to "the importance of proper bracketing" I would say that NONE of these are correct. a)$\displaystyle -(x+2) / x^2 + 2x - 8= -\frac{x+ 2}{x^2}+ 2x- 8$ is not correct. B) $\displaystyle -2-x / x^2+2x -8= -2- \frac{x}{x^2}+ 2x- 8$ is not correct. C) $\displaystyle -2-x / (x-2)(x+4)= -2- \frac{x}{(x-2)(x+4)}$ is not correct. D) $\displaystyle -x-2 / (x-2)(x+4)= -x- \frac{2}{(x- 2)(x+4)}$ is not correct. The correct answer is $\displaystyle -(x+ 2)/(x^2+ 2x- 8 )= -\frac{x+ 2}{x^2+ 2x- 8}= -\frac{x+ 2}{(x- 2)(x+ 4)}$. Tags fractions, linearalgebra Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Niiicck Algebra 2 October 16th, 2015 10:52 AM Zman15 Algebra 1 May 16th, 2015 06:39 AM Markmc1984 Algebra 5 April 13th, 2014 05:47 AM njc Algebra 8 August 29th, 2013 12:17 AM Infinite Elementary Math 2 February 13th, 2013 06:43 AM

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