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March 21st, 2018, 07:40 AM  #1 
Newbie Joined: Oct 2017 From: Georgia Posts: 4 Thanks: 0  Is there a way to get a fractional exponent from whole number exponents?
Is there a function or operator that I can apply to get the equivalent of the right side of this equation with whole Numbers on the left? f (a^(1/wholeNumberX) , a^(1/wholeNumberY) ) = a^(1.3) Last edited by Sixophrenia; March 21st, 2018 at 08:12 AM. 
March 21st, 2018, 07:56 AM  #2 
Senior Member Joined: May 2016 From: USA Posts: 1,310 Thanks: 550 
$\dfrac{1}{1.3} = \dfrac{1}{1} \div 1.3 = \dfrac{1}{1} \div \dfrac{13}{10} = \dfrac{1}{1} * \dfrac{10}{13} = \dfrac{10}{13}.$ $f(a,\ j,\ k) = a^{(j/k)} \implies f(a,\ 10,\ 13) = a^{(10/13)} = a^{(1/1.3)}.$ 
March 21st, 2018, 08:13 AM  #3  
Newbie Joined: Oct 2017 From: Georgia Posts: 4 Thanks: 0  Quote:
thanks oh wait. actually. I can't do that 10/13. I know that sucks. but it's a limitation of the programming language I'm in. Solidity. Maybe a Taylor series would work? I don't know. I am barely stringing things together. I may have to try to find a different way of figuring this out. Last edited by Sixophrenia; March 21st, 2018 at 08:35 AM.  
March 21st, 2018, 08:38 AM  #4  
Senior Member Joined: May 2016 From: USA Posts: 1,310 Thanks: 550  Quote:
 
March 21st, 2018, 09:04 AM  #5  
Newbie Joined: Oct 2017 From: Georgia Posts: 4 Thanks: 0  Quote:
It's just that division requires a number type that can't be directly supported. No floating point integers in Solidity. I think I basically have to abstract that with real integers  

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exponent, exponents, fractional, number 
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