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February 24th, 2018, 10:54 PM  #1 
Newbie Joined: Feb 2018 From: Viet Nam Posts: 2 Thanks: 0  System of equations 
February 24th, 2018, 11:20 PM  #2 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,749 Thanks: 613 Math Focus: Yet to find out. 
Cool.

February 25th, 2018, 04:57 AM  #3 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,785 Thanks: 970  
February 25th, 2018, 05:38 AM  #4  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,979 Thanks: 789 Math Focus: Wibbly wobbly timeywimey stuff.  Quote: Dan  
February 25th, 2018, 05:53 AM  #5 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,785 Thanks: 970  
February 25th, 2018, 06:41 AM  #6 
Math Team Joined: May 2013 From: The Astral plane Posts: 1,979 Thanks: 789 Math Focus: Wibbly wobbly timeywimey stuff.  Don't quote that unless you have the tentacles to back you up. ShubNiggurath! The goat with 1000 young! Dan Last edited by topsquark; February 25th, 2018 at 06:44 AM. 
February 25th, 2018, 08:19 AM  #7  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,979 Thanks: 789 Math Focus: Wibbly wobbly timeywimey stuff.  Quote: Dan  
February 25th, 2018, 10:35 AM  #8 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,785 Thanks: 970 
Sure is a monster! I'd start like this: a = 2x^2  y^2 + 2y b = x^2 + y  5 c = 3x^2  6y + 13 Then play with these: x^3  y^3 + 15x  3a = 10 3sqrt(y) + sqrt(b)  sqrt(c) = 0 Then substitute back in...I don't even wanna think about it !! 
February 25th, 2018, 02:54 PM  #9 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,785 Thanks: 970 
Just to "see", entered those 2 equations at Wolfram: WolframAlpha: Computational Knowledge Engine Now continue, doing the substitution... 

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