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 February 24th, 2018, 09:54 PM #1 Newbie   Joined: Feb 2018 From: Viet Nam Posts: 2 Thanks: 0 System of equations
 February 24th, 2018, 10:20 PM #2 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,610 Thanks: 550 Math Focus: Yet to find out. Cool.
February 25th, 2018, 03:57 AM   #3
Math Team

Joined: Oct 2011

Posts: 12,904
Thanks: 883

Quote:
 Originally Posted by Joppy Cool.
Why?

February 25th, 2018, 04:38 AM   #4
Math Team

Joined: May 2013
From: The Astral plane

Posts: 1,852
Thanks: 750

Math Focus: Wibbly wobbly timey-wimey stuff.
Quote:
 Originally Posted by NhiBosin
What have you been able to do?

-Dan

February 25th, 2018, 04:53 AM   #5
Math Team

Joined: Oct 2011

Posts: 12,904
Thanks: 883

Quote:
 Originally Posted by topsquark What have you been able to do? -Dan
Ph'nglui mglw'nafh Cthulhu R'lyeh wgah'nagl fhtagn.

February 25th, 2018, 05:41 AM   #6
Math Team

Joined: May 2013
From: The Astral plane

Posts: 1,852
Thanks: 750

Math Focus: Wibbly wobbly timey-wimey stuff.
Quote:
 Originally Posted by Denis Ph'nglui mglw'nafh Cthulhu R'lyeh wgah'nagl fhtagn.
Don't quote that unless you have the tentacles to back you up.

Shub-Niggurath! The goat with 1000 young!

-Dan

Last edited by topsquark; February 25th, 2018 at 05:44 AM.

February 25th, 2018, 07:19 AM   #7
Math Team

Joined: May 2013
From: The Astral plane

Posts: 1,852
Thanks: 750

Math Focus: Wibbly wobbly timey-wimey stuff.
Quote:
 Originally Posted by NhiBosin
This is a monster. If you can, please let us know where that equation comes from. That might give a hint on what to do.

-Dan

 February 25th, 2018, 09:35 AM #8 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,904 Thanks: 883 Sure is a monster! I'd start like this: a = 2x^2 - y^2 + 2y b = x^2 + y - 5 c = 3x^2 - 6y + 13 Then play with these: x^3 - y^3 + 15x - 3a = 10 3sqrt(y) + sqrt(b) - sqrt(c) = 0 Then substitute back in...I don't even wanna think about it !!
 February 25th, 2018, 01:54 PM #9 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,904 Thanks: 883 Just to "see", entered those 2 equations at Wolfram: Wolfram|Alpha: Computational Knowledge Engine Now continue, doing the substitution... Thanks from greg1313 and topsquark

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