My Math Forum I need help with this equation, it's URGENT.

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 February 17th, 2018, 11:01 AM #1 Newbie     Joined: Feb 2018 From: in a house with doors and windows Posts: 1 Thanks: 0 I need help with this equation, it's URGENT. I need to solve this exercise using the absolute value properties. The result must be in the form of an interval. I would appreciate it if you could send the solution written on a piece of paper. Thanks!!!... Math.png
 February 17th, 2018, 11:20 AM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,375 Thanks: 1276 \begin{align*} &\text{OK IT'S ON THE WAY!!!!}\\ \\ &\text{I ADDRESSED IT TO A HOUSE WITH DOORS AND WINDOWS} \\ \\ &\text{I'D GO WAIT BY THE MAILBOX UNTIL IT ARRIVES!} \end{align*} Thanks from topsquark, v8archie, Joppy and 3 others Last edited by romsek; February 17th, 2018 at 11:22 AM.
 February 17th, 2018, 11:31 AM #3 Senior Member     Joined: Sep 2015 From: USA Posts: 2,375 Thanks: 1276 but seriously folks... $|x+2| = |x+7|$ you can split this into 3 areas $x < -7$ $-7 \leq x \leq -2$ $-2 < x$ In area 1 we have $-(x+2) = -(x+7)$ $x+2 = x+7$ $0 = 5$ and thus there are no solutions to this equation in area 1 In area 2 we have $-(x+2) = x+7$ $-x -2 = x+7$ $-9 = 2x$ $x = -\dfrac 9 2$ In area 3 we have $(x+2) = (x+7)$ and again it should be clear that there are no solutions to this in area 3 So there is only one solution to this equation and that is $x = -\dfrac 9 2$ You talk about wanting the solution as intervals. This suggests to me that the expression in question should actually be an inequality. Not an equality. Have you expressed the question correctly? Thanks from topsquark
 February 17th, 2018, 11:35 AM #4 Senior Member   Joined: May 2016 From: USA Posts: 1,310 Thanks: 550 HINT: $|x + 2| = |x + 7| \implies x + 2 = x + 7 \text { or } x + 2 = -\ (x + 7).$ Now what? Thanks from topsquark
 February 17th, 2018, 11:37 AM #5 Senior Member   Joined: Nov 2011 Posts: 250 Thanks: 3 It's not my equation, but I want to understand the solution in the beginning part: but seriously folks... $|x+2| = |x+7|$ you can split this into 3 areas *$x < -7$ *$-7 \leq x \leq -2$ *$-2 < x$ In what way you get the (*) inequation? Last edited by skipjack; February 17th, 2018 at 06:56 PM.
February 17th, 2018, 12:08 PM   #6
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Quote:
 Originally Posted by shaharhada It's not my equation, but I want to understand the solution in the beginning part: but seriously folks... $|x+2| = |x+7|$ you can split this into 3 areas *$x < -7$ *$-7 \leq x \leq -2$ *$-2 < x$ In what way you get the (*) inequation?
I specified 3 separate sub-domains. There is no derivation involved.

Last edited by skipjack; February 17th, 2018 at 06:56 PM.

February 17th, 2018, 12:09 PM   #7
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Quote:
 Originally Posted by JeffM1 Now what?
DisneyWorld?

February 17th, 2018, 01:39 PM   #8
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Quote:
 Originally Posted by maverick71 solution written on a piece of paper.
solution
---------
paper/x
where x > 1

 February 17th, 2018, 04:20 PM #9 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,769 Thanks: 626 Math Focus: Yet to find out. . Damn this forum is good.
February 17th, 2018, 04:38 PM   #10
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Quote:
 Originally Posted by romsek DisneyWorld?
No thanks. Went in January ... an expensive lesson in “hurry up & wait”

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