My Math Forum Complex Number to Polar form with Real = 0!!!

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 December 27th, 2017, 04:09 AM #1 Senior Member   Joined: Oct 2015 From: Greece Posts: 137 Thanks: 8 Complex Number to Polar form with Real = 0!!! Hello! I have this complex number: $0 + j\times 89,75$ Our professor told us $0 + j\times 89,75$ to polar is: $89,75\angle 90$ He also told us Cartesian to polar convertion: $\sqrt{a^{2}+b^{2}}\angle{\tan^{-1}(b/a)}$ So let's convert $0 + j\times 89,75$ to polar: First of all $\sqrt{a^{2}+b^{2}} = \sqrt{0^{2}+89,75^{2}} = 89,75$ but: $\tan^{-1}(b/a)$ , a = 0!!!!! So how? Last edited by skipjack; December 27th, 2017 at 09:22 AM.
December 27th, 2017, 06:36 AM   #2
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 Originally Posted by babaliaris Hello! I have this complex number: $0 + j\times 89,75$ Our professor told us $0 + j\times 89,75$ to polar is: $89,75\angle 90$ He also told as cartesian to polar conversation: $\sqrt{a^{2}+b^{2}}\angle{\tan^{-1}(b/a)}$ So let's convert $0 + j\times 89,75$ to polar: First of all $\sqrt{a^{2}+b^{2}} = \sqrt{0^{2}+89,75^{2}} = 89,75$ but: $\tan^{-1}(b/a)$ , a = 0!!!!! So how?
$\tan\left(\dfrac{\pi}{2} \right)$ is undefined, as is $\dfrac{b}{a}$ when $a=0$

 December 27th, 2017, 03:15 PM #3 Senior Member   Joined: Sep 2016 From: USA Posts: 669 Thanks: 440 Math Focus: Dynamical systems, analytic function theory, numerics You can't learn math if you still think its just a bunch of formulas. Put down the formula and just look at the vector you have written and tell me its polar angle. Once you do this, you will easily see how to correct the formula to account for this case. Thanks from Maschke
December 28th, 2017, 12:21 PM   #4
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 Originally Posted by SDK You can't learn math if you still think its just a bunch of formulas. Put down the formula and just look at the vector you have written and tell me its polar angle. Once you do this, you will easily see how to correct the formula to account for this case.

Sometimes you need to think before you ask something i guess

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