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December 27th, 2017, 04:09 AM  #1 
Member Joined: Oct 2015 From: Greece Posts: 33 Thanks: 0  Complex Number to Polar form with Real = 0!!!
Hello! I have this complex number: $0 + j\times 89,75$ Our professor told us $0 + j\times 89,75$ to polar is: $89,75\angle 90$ He also told us Cartesian to polar convertion: $\sqrt{a^{2}+b^{2}}\angle{\tan^{1}(b/a)}$ So let's convert $0 + j\times 89,75$ to polar: First of all $\sqrt{a^{2}+b^{2}} = \sqrt{0^{2}+89,75^{2}} = 89,75$ but: $\tan^{1}(b/a)$ , a = 0!!!!! So how? Last edited by skipjack; December 27th, 2017 at 09:22 AM. 
December 27th, 2017, 06:36 AM  #2  
Math Team Joined: Jul 2011 From: Texas Posts: 2,724 Thanks: 1378  Quote:
 
December 27th, 2017, 03:15 PM  #3 
Senior Member Joined: Sep 2016 From: USA Posts: 320 Thanks: 164 Math Focus: Dynamical systems, analytic function theory, numerics 
You can't learn math if you still think its just a bunch of formulas. Put down the formula and just look at the vector you have written and tell me its polar angle. Once you do this, you will easily see how to correct the formula to account for this case.

December 28th, 2017, 12:21 PM  #4  
Member Joined: Oct 2015 From: Greece Posts: 33 Thanks: 0  Quote:
Sometimes you need to think before you ask something i guess  

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complex, form, number, polar, real 
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