November 17th, 2017, 08:51 PM  #1 
Senior Member Joined: Jul 2011 Posts: 399 Thanks: 15  Binomial Sum
Prove that $\displaystyle \displaystyle \binom{n}{1}\left(1+\frac{1}{2}\right)\binom{n}{2}+\left(1+ \frac{1}{2}+\frac{1}{3}\right)\binom{n}{3}+\cdots \cdots \cdots +(1)^n\left(1+\frac{1}{2}+\frac{1}{3}+\cdots \cdots +\frac{1}{n}\right)=\frac{1}{n}$
Last edited by panky; November 17th, 2017 at 08:53 PM. 

Tags 
binomial, sum 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
How to resolve binomial experiment without binomial theorem.  beesee  Probability and Statistics  5  September 18th, 2015 01:38 PM 
Binomial GCD  Randompn  Number Theory  10  November 21st, 2012 01:25 PM 
Binomial Qns!  muhsentdrawjiac  Probability and Statistics  17  June 28th, 2012 05:24 PM 
Binomial  jsmith613  Probability and Statistics  3  October 16th, 2011 08:51 AM 
Sum of two Binomial r.v.  jer2145  Advanced Statistics  0  March 6th, 2010 06:06 PM 