My Math Forum Integer Exponents.....When an automobile accelerates,....

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November 14th, 2017, 03:35 PM   #1
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Integer Exponents.....When an automobile accelerates,....

Hello I am just stuck on how to do D...

Here are the answers and the work for b and c

Thanks for any help.
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 November 14th, 2017, 04:11 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,878 Thanks: 1087 Math Focus: Elementary mathematics and beyond Got a bigger picture of the questions? Or type it out... Thanks from topsquark and GIjoefan1976
November 14th, 2017, 05:15 PM   #3
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maybe this?

or does this work better?
if you increase your speed by 50% by what factor does the power requirement increase?
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Last edited by GIjoefan1976; November 14th, 2017 at 05:20 PM. Reason: more info

 November 15th, 2017, 03:37 AM #4 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,261 Thanks: 894 I see nothing after "maybe this" and "or does this work better" is not much better than what you had originally. But I can read the table of values. Notice that $\displaystyle \frac{2840}{355}= 8= 2^3$, $\displaystyle \frac{9585}{355}= 27= 3^3$, $\displaystyle \frac{22720}{355}= 64= 4^3$. Of course, the same fractions for the x values are 2, 3, and 4. That is, for each of those we can write the function as $\displaystyle P= 355\left(\frac{v}{10}\right)^3$. The 'integer exponent' here is '3'!
November 15th, 2017, 12:15 PM   #5
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Quote:
 Originally Posted by Country Boy I see nothing after "maybe this" and "or does this work better" is not much better than what you had originally. But I can read the table of values. Notice that $\displaystyle \frac{2840}{355}= 8= 2^3$, $\displaystyle \frac{9585}{355}= 27= 3^3$, $\displaystyle \frac{22720}{355}= 64= 4^3$. Of course, the same fractions for the x values are 2, 3, and 4. That is, for each of those we can write the function as $\displaystyle P= 355\left(\frac{v}{10}\right)^3$. The 'integer exponent' here is '3'!
Hmm Okay as I made the picture bigger I guess I could have cropped sections out, if it is not the whole picture that is needed?

I then typed out the question I was stuck on....

If you increase your speed by 50% by what factor does the power requirement increase?

so am I suppose to see it as being raised to 15 as wouldn't 20 be a 100 percent?...the answer they got was 3.375

November 15th, 2017, 12:53 PM   #6
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Quote:
 If you increase your speed by 50% by what factor does the power requirement increase?
$\dfrac{P_f}{P_i} = \dfrac{0.355v_f^3}{0.355v_i^3} = \dfrac{0.355(1.5v_i)^3}{0.355v_i^3} = 1.5^3$

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