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November 14th, 2017, 04:35 PM   #1
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Integer Exponents.....When an automobile accelerates,....

Hello I am just stuck on how to do D...

Here are the answers and the work for b and c

Thanks for any help.
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November 14th, 2017, 05:11 PM   #2
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Got a bigger picture of the questions? Or type it out...
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November 14th, 2017, 06:15 PM   #3
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maybe this?


or does this work better?
if you increase your speed by 50% by what factor does the power requirement increase?
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November 15th, 2017, 04:37 AM   #4
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I see nothing after "maybe this" and "or does this work better" is not much better than what you had originally. But I can read the table of values.

Notice that $\displaystyle \frac{2840}{355}= 8= 2^3$, $\displaystyle \frac{9585}{355}= 27= 3^3$, $\displaystyle \frac{22720}{355}= 64= 4^3$. Of course, the same fractions for the x values are 2, 3, and 4. That is, for each of those we can write the function as $\displaystyle P= 355\left(\frac{v}{10}\right)^3$. The 'integer exponent' here is '3'!
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November 15th, 2017, 01:15 PM   #5
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Quote:
Originally Posted by Country Boy View Post
I see nothing after "maybe this" and "or does this work better" is not much better than what you had originally. But I can read the table of values.

Notice that $\displaystyle \frac{2840}{355}= 8= 2^3$, $\displaystyle \frac{9585}{355}= 27= 3^3$, $\displaystyle \frac{22720}{355}= 64= 4^3$. Of course, the same fractions for the x values are 2, 3, and 4. That is, for each of those we can write the function as $\displaystyle P= 355\left(\frac{v}{10}\right)^3$. The 'integer exponent' here is '3'!
Hmm Okay as I made the picture bigger I guess I could have cropped sections out, if it is not the whole picture that is needed?

I then typed out the question I was stuck on....

If you increase your speed by 50% by what factor does the power requirement increase?

so am I suppose to see it as being raised to 15 as wouldn't 20 be a 100 percent?...the answer they got was 3.375
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November 15th, 2017, 01:53 PM   #6
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Quote:
If you increase your speed by 50% by what factor does the power requirement increase?
$\dfrac{P_f}{P_i} = \dfrac{0.355v_f^3}{0.355v_i^3} = \dfrac{0.355(1.5v_i)^3}{0.355v_i^3} = 1.5^3$
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