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November 7th, 2017, 08:03 AM  #1 
Newbie Joined: Nov 2017 From: New Jersey Posts: 2 Thanks: 0  absolute equations
Hi All, what would be the best way to solve for x: 13x7 + 11 = 7x7 + 11 I started subtracting 11 from both sides and then dividing both sides by 13, but then got stuck with how to isolate the x. Thanks in advance. 
November 7th, 2017, 08:37 AM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,797 Thanks: 715 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
13y + 11 = 7y + 11 Cancel the 11. 13y = 7y What value can y take? Once you have that you know that you can use the definition of p: $\displaystyle p = \begin{cases} p & p \leq 0 \\ p & 0 < p \end{cases}$ Can you finish from here? Dan  
November 7th, 2017, 05:23 PM  #3 
Newbie Joined: Nov 2017 From: New Jersey Posts: 2 Thanks: 0 
Yes, I think I can. Thank you.

November 8th, 2017, 04:24 AM  #4  
Math Team Joined: Jan 2015 From: Alabama Posts: 3,195 Thanks: 872  I presume you meant "Let y= x 7." Quote:
$\displaystyle p = \begin{cases} p & p \geq 0 \\ p & p < 0 \end{cases}$ Last edited by Country Boy; November 8th, 2017 at 04:28 AM.  
November 8th, 2017, 07:14 AM  #5 
Math Team Joined: May 2013 From: The Astral plane Posts: 1,797 Thanks: 715 Math Focus: Wibbly wobbly timeywimey stuff.  

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