October 21st, 2017, 12:24 PM | #1 |
Newbie Joined: Oct 2017 From: Toronto Posts: 6 Thanks: 0 | E=mc2
Is E=mc2 considered a "cubic" equation? What is the term to describe "multi-ordered" equations? Meaning...more than two degrees in order? Polynomials? |
October 21st, 2017, 03:43 PM | #2 |
Math Team Joined: Dec 2013 From: Colombia Posts: 7,403 Thanks: 2477 Math Focus: Mainly analysis and algebra |
No, it's linear in mass and energy. The speed of light is usually considered to be constant. An expression of the form $(a_nx^n + a_{n-1}x^{n-1} + \ldots + a_2x^2 + a_1x + a_0)$ is a polynomial (in a single variable). A more general expression with a finite number of terms of the form $ a x_1^{p_1} x_2^{p_2} \ldots x_n^{p_n}$ is a polynomial in $n$ variables. |
October 21st, 2017, 04:02 PM | #3 |
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,133 Thanks: 914 |
Go read-up: E=mc^2 - An Explanation of the Basics and Units |
October 22nd, 2017, 05:24 PM | #4 | |
Newbie Joined: Oct 2017 From: Toronto Posts: 6 Thanks: 0 | Quote:
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October 23rd, 2017, 09:06 AM | #5 |
Math Team Joined: Jan 2015 From: Alabama Posts: 3,261 Thanks: 894 |
What you are writing as "c2" would better be written as "c^2" or, even better, "$\displaystyle c^2$". It is "c times c" or "c squared" and c is the speed of light.
Last edited by skipjack; October 23rd, 2017 at 03:13 PM. |
October 23rd, 2017, 11:07 AM | #6 | |
Senior Member Joined: Jun 2015 From: England Posts: 853 Thanks: 258 | Quote:
Relativistic Energy It also explains that the famous formula so often quoted is incomplete as $\displaystyle E = m{c^2}$ | |
October 24th, 2017, 01:48 AM | #7 | |
Senior Member Joined: Apr 2014 From: Glasgow Posts: 2,127 Thanks: 716 Math Focus: Physics, mathematical modelling, numerical and computational solutions | Quote:
$\displaystyle E^2 = m^2c^4 + p^2 c^2$ where E is kinetic energy (J), m is mass (kg), c is 299792458 m/s and p is momentum (kg m/s). The case when $\displaystyle p = 0$ gives Einstein's famous equation. | |