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October 19th, 2017, 07:52 AM  #1 
Newbie Joined: Oct 2017 From: Sweden Posts: 1 Thanks: 0  Reducing fractions to its simplest form ( with exponents)
Hello! I'd like some help with a few problems that I have with reducing certain fractions to its simplest form. I already know the answers since they are written down in my book; what I need help with is how to think, explanation. Here are the problems: a) 3AB^3/18A^3B b) 10X^3/15X^2 c) 2X+2/2X Thanks. Last edited by skipjack; October 19th, 2017 at 08:02 AM. 
October 19th, 2017, 08:18 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,845 Thanks: 1567 
In each fraction, identify any factor (other than 1) of every term of the numerator that is also a factor of every term of the denominator, then remove that factor from both the numerator and the denominator (this amounts to dividing every term by the factor). (c) 2X + 2 and 2X have 2 as a common factor. To remove 2 from the second term of the numerator, replace that term with 1. Hence the result is (X + 1)/X. This assumes that the original fraction was intended to be (2X + 2)/(2X). Having removed a common factor, repeat the process if another common factor still exists. Is that sufficient explanation? 
October 19th, 2017, 09:36 AM  #3 
Math Team Joined: May 2013 From: The Astral plane Posts: 1,765 Thanks: 707 Math Focus: Wibbly wobbly timeywimey stuff.  Hmmm... Seems I'm doing the "pet peeve" thing today. Warning! Warning!! Pet peeve alert! Warning! a) (3AB^3)/(18A^3B) b) (10X^3)/(15X^2) c) (2X + 2)/(2X) The parentheses are important. For example, using order of operations: a) 3AB^3/18A^3B = (3AB^3/18 ) * A^3B = (3AB^3 * A^3B)/18 which is not at all what you were trying to say. See here: Order of operations. Pet peeve ended. I'm all better now! Dan 

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exponents, form, fractions, reducing, simplest 
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