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August 28th, 2017, 05:43 PM   #1
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Find a circle's equation

After giving the equation for circles ( $\displaystyle (x - h)^{2} + (y - k)^{2} = r^{2}$ , the question says:

"Find the equation of a circle with radius of 3 and center (-2, 5)."

At first I solved for x and y individually by respectively substituting the other with 0 (i.e. solving for y: $\displaystyle (0 + 2)^2 + (y - 5)^2 = 9$)

But is it just asking for this:

$\displaystyle (x + 2)^2 + (y - 5)^2 = 9$

?

It's on a review sheet with many many different topics, so this is the only of its kind I can look at; no other examples of this sort.
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August 28th, 2017, 07:10 PM   #2
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you just have to plug in

$h=-2$

$k=5$

$r=3$
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August 28th, 2017, 07:52 PM   #3
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Okay, thank you! I'll respond to your reply on my other question probably tomorrow. (Changing a proportion by adding more) I just had a bunch of birthday cake and I'm getting sleepy, so my brain's not processing things properly.
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