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August 19th, 2017, 06:34 AM   #1
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Is logarithm a arithmetic operation?
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August 19th, 2017, 07:31 AM   #2
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As far as I know, addition, subtraction, multiplication, and division are arithmetic operations.

a logarithm is the inverse of an exponential operation, i.e. $y = a^x \implies x = \log_a{y}$
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August 19th, 2017, 07:45 AM   #3
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The basic operations of arithmetic are addition , subtraction , multiplication and division (as skeeter has pointed out). These are called binary operations because they are done between 2 numbers. A logarithm is the exponent upon the base.

$log_{a}b = c \iff a^c = b $

I suppose one can define

$ \ \ \ a \circ b = a^b $

but this is a more advanced binary abstraction. if your question is elementary then a logarithm is not an arithmetic operation.

If you are asking how logarithms are computed , they are computed using the basic operations of arithmetic (except in very easy special cases where the answer is obvious by inspection)

Last edited by agentredlum; August 19th, 2017 at 07:48 AM.
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