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August 5th, 2017, 04:23 AM  #1 
Newbie Joined: Apr 2017 From: Canada Posts: 22 Thanks: 1  Help with modules
Please help me prove the following theorem: This theorem apparently holds when $\displaystyle p$ is prime, and $\displaystyle a $ is NOT a multiple of $\displaystyle p$. If, $\displaystyle ab = ac $ $\displaystyle mod(p)$ Then $\displaystyle b = c $ $\displaystyle mod(p)$ 
August 5th, 2017, 05:04 AM  #2 
Senior Member Joined: Oct 2009 Posts: 141 Thanks: 59 
When is $a$ invertible? I.e. can you find an $x$ such that $ax=1$ mod(p)?

August 5th, 2017, 08:52 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 17,725 Thanks: 1359 
The standard notation, for example, $\displaystyle ab \equiv ac \pmod p$, is preferred.

August 5th, 2017, 04:55 PM  #4 
Senior Member Joined: Oct 2009 Posts: 141 Thanks: 59  
August 5th, 2017, 04:58 PM  #5 
Global Moderator Joined: Dec 2006 Posts: 17,725 Thanks: 1359 
What I meant was "preferred on this website".


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