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August 2nd, 2017, 10:53 AM  #11 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,745 Thanks: 1001 Math Focus: Elementary mathematics and beyond  As 3 has only 1 and 3 as (positive) factors, 3x$^2$ + 19x + 6 = (3x + a)(x + b) Now find a and b so that a * b = 6 and 3b + a = 19 hold. Last edited by greg1313; August 2nd, 2017 at 10:56 AM. 
August 2nd, 2017, 11:12 AM  #12  
Senior Member Joined: May 2016 From: USA Posts: 904 Thanks: 359  Quote:
$ax^2 + bx + c = a * \left ( x + \dfrac{b + d}{2a} \right ) \left ( x + \dfrac{b  d}{2a} \right), \text { where } d = \sqrt{b^2  4ac}.$  

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curious, factoring, high, school 
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