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June 27th, 2017, 04:40 AM  #1 
Newbie Joined: Jun 2017 From: Bulgaria Posts: 1 Thanks: 0  Very interesting System Can you help me get to the solutions of the system and show me the way of working it out? Good luck. Last edited by skipjack; June 27th, 2017 at 11:08 AM. 
June 27th, 2017, 11:20 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 17,919 Thanks: 1386 
Substituting y = 28  x² in the second equation gives x + (28  x²)² = 14, which simplifies to (x  5)(x³ + 5x²  31x  154) = 0. Hence x = 5 or x³ + 5x²  31x  154 = 0. The second equation has three real roots, but they aren't integers. 

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