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 June 27th, 2017, 04:40 AM #1 Newbie   Joined: Jun 2017 From: Bulgaria Posts: 1 Thanks: 0 Very interesting System Can you help me get to the solutions of the system and show me the way of working it out? Good luck. Last edited by skipjack; June 27th, 2017 at 11:08 AM.
 June 27th, 2017, 11:20 AM #2 Global Moderator   Joined: Dec 2006 Posts: 21,036 Thanks: 2273 Substituting y = 28 - x² in the second equation gives x + (28 - x²)² = 14, which simplifies to (x - 5)(x³ + 5x² - 31x - 154) = 0. Hence x = 5 or x³ + 5x² - 31x - 154 = 0. The second equation has three real roots, but they aren't integers.

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