My Math Forum Not sure what theme it is, some help!

 Algebra Pre-Algebra and Basic Algebra Math Forum

 June 6th, 2017, 09:15 PM #1 Newbie   Joined: Dec 2016 From: Argentina Posts: 5 Thanks: 0 Not sure what theme it is, some help! I am going to make this question in Calculus because I am not sure where it should be, please tell me if I have to do this question in another place. When (a+b)/(4)-(b+c)/(5)+(c+a)/(6) then ratio a:b:c=1 : FIRST ANSWER : SECOND ANSWER. I have no idea what is this, not very smart with math. Thank you!
 June 6th, 2017, 09:33 PM #2 Senior Member   Joined: May 2016 From: USA Posts: 1,038 Thanks: 423 I at least have no idea what you are talking about. Please give the complete problem exactly as stated.
 June 7th, 2017, 06:53 AM #3 Newbie   Joined: Dec 2016 From: Argentina Posts: 5 Thanks: 0 That is the entire exercise! Last edited by Asami; June 7th, 2017 at 07:00 AM.
 June 14th, 2017, 04:12 AM #4 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,197 Thanks: 872 "When (a+b)/(4)-(b+c)/(5)+(c+a)/(6) then" makes no sense! In "when A then B", A has to be a complete statement. "When (a+b)/(4)-(b+c)/(5)+(c+a)/(6)" is what? Was this equal to something?

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