
Algebra PreAlgebra and Basic Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
June 6th, 2017, 09:15 PM  #1 
Newbie Joined: Dec 2016 From: Argentina Posts: 5 Thanks: 0  Not sure what theme it is, some help!
I am going to make this question in Calculus because I am not sure where it should be, please tell me if I have to do this question in another place. When (a+b)/(4)(b+c)/(5)+(c+a)/(6) then ratio a:b:c=1 : FIRST ANSWER : SECOND ANSWER. I have no idea what is this, not very smart with math. Thank you! 
June 6th, 2017, 09:33 PM  #2 
Senior Member Joined: May 2016 From: USA Posts: 1,038 Thanks: 423 
I at least have no idea what you are talking about. Please give the complete problem exactly as stated.

June 7th, 2017, 06:53 AM  #3 
Newbie Joined: Dec 2016 From: Argentina Posts: 5 Thanks: 0 
That is the entire exercise! Last edited by Asami; June 7th, 2017 at 07:00 AM. 
June 14th, 2017, 04:12 AM  #4 
Math Team Joined: Jan 2015 From: Alabama Posts: 3,197 Thanks: 872 
"When (a+b)/(4)(b+c)/(5)+(c+a)/(6) then" makes no sense! In "when A then B", A has to be a complete statement. "When (a+b)/(4)(b+c)/(5)+(c+a)/(6)" is what? Was this equal to something? 

Tags 
ratio, theme 
Thread Tools  
Display Modes  
