May 16th, 2017, 12:12 PM  #11 
Global Moderator Joined: Dec 2006 Posts: 19,065 Thanks: 1621 
From what you posted, I assume that the ladder's position is the hypotenuse of length (h + 2)feet of a rightangled triangle whose base is a horizontal line 10 feet long from the foot of the ladder to the foot of a vertical wall, and whose height is the height of the position on the wall where the top of the ladder rests. By Pythagoras, h² + 10² = (h + 2)², which implies h² + 100 = h² + 4h + 4. Hence h = (100  4)/4 = 24, which means that the ladder reached a point 24 feet up the wall. If that's all that had to be done for the ladder problem, we just need your answers for the later parts of the deer population problem, as the answers already shown are correct. 
May 16th, 2017, 12:15 PM  #12  
Senior Member Joined: Feb 2016 From: seattle Posts: 377 Thanks: 10  Quote:
Thanks skipjack  
May 16th, 2017, 12:16 PM  #13  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,621 Thanks: 845  Quote:
ONLY 1 problem is showing: about deer population. What have you been smoking?  
May 16th, 2017, 05:09 PM  #14 
Senior Member Joined: Feb 2016 From: seattle Posts: 377 Thanks: 10  I would change it out but I don't know how to change the attachment if I am even able to? I am glad to know it may help people but this seems to be out of control. (and of course yes I know my doing my best caused the ball rolling) I originally was going to post the deer one but figured it out, but now with it being the next day I don't have the work anymore.

May 16th, 2017, 05:13 PM  #15 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,621 Thanks: 845 
Good nuff. Carry on...


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base, end, feet, ladder, wall 
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