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 May 5th, 2017, 09:18 PM #1 Senior Member   Joined: Jan 2017 From: US Posts: 111 Thanks: 6 How To Construct This Equation I think this is fairly simple, I just want to make sure I set up the equation right: A jet can fly 300 miles in the same time that it takes a prop plane to travel 120 miles. If the prop plane travels at a speed of 90 mph slower than the jet, find the speed of the jet. I'm guessing the y=k(x) formula would apply here?
 May 6th, 2017, 01:11 AM #2 Global Moderator   Joined: Dec 2006 Posts: 19,058 Thanks: 1618 As 300 miles is 180 miles greater than 120 miles, the journeys would take (180/90) hours, which is 2 hours. Hence the jet flies at 150mph and the prop plane at 60mph. The above uses the time = distance/speed and speed = distance/time relationships, which are essentially equivalent to distance = speed × time. Thanks from Indigo28
May 6th, 2017, 11:35 PM   #3
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Quote:
 Originally Posted by skipjack As 300 miles is 180 miles greater than 120 miles, the journeys would take (180/90) hours, which is 2 hours. Hence the jet flies at 150mph and the prop plane at 60mph. The above uses the time = distance/speed and speed = distance/time relationships, which are essentially equivalent to distance = speed × time.
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