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May 5th, 2017, 10:18 PM   #1
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How To Construct This Equation

I think this is fairly simple, I just want to make sure I set up the equation right:

A jet can fly 300 miles in the same time that it takes a prop plane to travel 120 miles. If the prop plane travels at a speed of 90 mph slower than the jet, find the speed of the jet.

I'm guessing the y=k(x) formula would apply here?
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May 6th, 2017, 02:11 AM   #2
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As 300 miles is 180 miles greater than 120 miles, the journeys would take (180/90) hours, which is 2 hours. Hence the jet flies at 150mph and the prop plane at 60mph.

The above uses the time = distance/speed and speed = distance/time relationships, which are essentially equivalent to distance = speed × time.
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May 7th, 2017, 12:35 AM   #3
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Quote:
Originally Posted by skipjack View Post
As 300 miles is 180 miles greater than 120 miles, the journeys would take (180/90) hours, which is 2 hours. Hence the jet flies at 150mph and the prop plane at 60mph.

The above uses the time = distance/speed and speed = distance/time relationships, which are essentially equivalent to distance = speed × time.
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