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May 5th, 2017, 09:18 PM  #1 
Senior Member Joined: Jan 2017 From: US Posts: 104 Thanks: 5  How To Construct This Equation
I think this is fairly simple, I just want to make sure I set up the equation right: A jet can fly 300 miles in the same time that it takes a prop plane to travel 120 miles. If the prop plane travels at a speed of 90 mph slower than the jet, find the speed of the jet. I'm guessing the y=k(x) formula would apply here? 
May 6th, 2017, 01:11 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,847 Thanks: 1568 
As 300 miles is 180 miles greater than 120 miles, the journeys would take (180/90) hours, which is 2 hours. Hence the jet flies at 150mph and the prop plane at 60mph. The above uses the time = distance/speed and speed = distance/time relationships, which are essentially equivalent to distance = speed × time. 
May 6th, 2017, 11:35 PM  #3  
Senior Member Joined: Jan 2017 From: US Posts: 104 Thanks: 5  Quote:
 

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