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 May 2nd, 2017, 04:17 AM #1 Newbie   Joined: May 2017 From: australia Posts: 4 Thanks: 0 I am not sure whether there is an equation to approach the value My cousin was doing some maths, but he did not have any idea how to resolve it. I don't know equation, so I post it here and hope someone kindly help him figure out whether there is an equation that can approximate the value of X. Here are the results, but with an unknown value x: When Altitude (y) = 0.119, f(y) = 4.9 Altitude (y) = 0.1199, f(y) = 4.99 Altitude (y) = 0.11999, f(y) = 4.999 Altitude (y) = 0.12, f(y) = x Altitude (y) = 0.12001, f(y) = 5.001 Altitude (y) = 0.1201, f(y) = 5.01 Altitude (y) = 0.121, f(y) = 5.1 What is the value of x? This is my first time posting a maths question in this forum; please forgive me if my questions violate the rules. Thank you. Last edited by skipjack; May 2nd, 2017 at 10:34 AM. May 2nd, 2017, 06:03 AM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 2,982 Thanks: 1575 here is one possible function that is continuous ... $f(y) = 100y-7 \implies f(0.12) = 5$ then again, here is a function with a discontinuity at $y=0.12$, i.e., $f(0.12)$ is undefined, but will yield the same values as given in your table ... $f(y) = \dfrac{(100y-7)(100y-12)}{100y-12}$ May 2nd, 2017, 06:22 AM   #3
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 Originally Posted by kittystackexchange My cousin was doing some maths, but he did not have any idea how to resolve it. May 2nd, 2017, 06:29 AM   #4
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 Originally Posted by Denis Why can't your "cousin" ask for help on his own?
Thank you Denis.
I can't tell you much about my profile.
(She is korean and her English isn't good enough)

Last edited by kittystackexchange; May 2nd, 2017 at 06:45 AM. May 2nd, 2017, 06:30 AM   #5
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 Originally Posted by skeeter here is one possible function that is continuous ... $f(y) = 100y-7 \implies f(0.12) = 5$ then again, here is a function with a discontinuity at $y=0.12$, i.e., $f(0.12)$ is undefined, but will yield the same values as given in your table ... $f(y) = \dfrac{(100y-7)(100y-12)}{100y-12}$
Many thanks for the quick help, skeeter!

Last edited by kittystackexchange; May 2nd, 2017 at 06:43 AM. May 2nd, 2017, 07:36 AM #6 Newbie   Joined: May 2017 From: australia Posts: 4 Thanks: 0 I wanted to add some more information, but the edit button is gone May 2nd, 2017, 08:02 AM   #7
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 Originally Posted by kittystackexchange I wanted to add some more information, but the edit button is gone
"Quote" your post and edit for a new post ... Tags approach, equation Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post VisionaryLen Calculus 19 October 28th, 2016 11:29 AM zaff9 Abstract Algebra 7 September 20th, 2013 11:50 PM akle Calculus 1 July 9th, 2010 10:11 AM cmmcnamara Advanced Statistics 4 February 10th, 2010 05:49 AM

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