May 1st, 2017, 04:43 AM  #1 
Senior Member Joined: Apr 2010 Posts: 448 Thanks: 1  inequality
If for all x,y and a>0 we have ; $\displaystyle \sqrt{x^2+y^2}<a$ then find a b>0 such that: $\displaystyle \sqrt{(zx)^2+(wy)^2}<b\Longrightarrow\sqrt{z^2+w^2}<a$ for all z,w 

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